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Shtirlitz [24]
2 years ago
9

1. Cp is smaller than Hx

Chemistry
1 answer:
andreev551 [17]2 years ago
8 0
1 has a higher ionization dismal aoa
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In which step of a four-stroke engine cycle does the car release CO2, H2O, and CO?
In-s [12.5K]

Answer:

\boxed{\text{exhaust stroke}}

Explanation:

The four strokes are

  1. Intake: The mixture of air and fuel enters the cylinder.
  2. Compression: The mixture is compressed by a factor of about 11.
  3. Ignition: A spark ignites the fuel, which burns and produces CO₂, CO, and H₂O.
  4. Exhaust: The combustion products are expelled from the cylinder.

\text{The cylinder releases CO$_{2}$, CO, and H$_{2}$O during the }\boxed{\textbf{exhaust stroke}}

7 0
3 years ago
You have just discovered a new organism.it is a single cell and has a cell wall but no nucleus. What kind of organism is it? Exp
jolli1 [7]
If it is a single cell then it is unicellular. it is an animal cell if it ha no cell wall and cells without nucleus are prokaryotes so it could be a Monera like bacteria.
8 0
3 years ago
A liquid that occupies a volume of 0.820 L has a mass of 2.56 kg.
user100 [1]

Answer:

The density of this liquid is 0.320 kg/L

Explanation:

Given:

Volume of the Liquid =  0.820 L

Mass of the liquid  = 2.56 kg.

To Find:

The density of the liquid in  kg/L

Solution:

Density is the mass occupied by the substance in unit volume. This density is essential determining whether the substance floats or sinks. Greek letter(rho) is used to denote density

The equation of for density is

Density = \frac{mass}{volume}

\rho = \frac{m}{v}

where m is the mass

v is the volume

On substituting the given values

\rho = \frac{0.820 }{2.56}

\rho = 0.320 kg/L

7 0
3 years ago
if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
3 years ago
What effect would increasing the amount of air surrounding the apple have on the apple ?
CaHeK987 [17]

Answer:

It has been suggested that climate change, which would generally lead to warmer winters in the Northeast, may make it difficult to produce some apple varieties in parts of the region. ... Greater variability in weather, such as warm periods followed by cold snaps in winter, can damage both flower buds and trees.

Explanation:

4 0
2 years ago
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