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ValentinkaMS [17]
3 years ago
14

Need help with this can some please help

Chemistry
1 answer:
vekshin13 years ago
7 0
I believe you would just put a 2 in front of NH3 and keep the other ones as 1
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Which of the following substances would be a good electrical conductor? A. KCl(s) B. C(s) C. Al(s) D. CO2(s)
finlep [7]
The correct answer would be B
8 0
3 years ago
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5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
Which graph best shows the relationship between kelvin temperature and average kinetic energy?
dolphi86 [110]

Answer:

The Kelvin temperature scale reflects the relationship between temperature and average kinetic energy.

Explanation:

The Kelvin temperature of a substance is directly equal to the average kinetic energy of the particles of a substance.

3 0
3 years ago
Read 2 more answers
He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→l
AURORKA [14]

 2 Li(s)  +Cl₂→  2 Li⁺ (aq)  + 2Cl⁻ (aq)

The cell potential   of  the reaction above   is +4.40V

<em><u>calculation</u></em>

Cell  potential  =∈° red - ∈° oxidation

in  reaction above  Li  is  oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

  Cl  is  reduce   from oxidation  state 0 to -1 therefore  the ∈°red = +1.36 V

cell  potential is therefore = +1.36 v -- 3.04  = + 4.40 V

3 0
3 years ago
in the laboratory, a group of students was assigned to determine the density of an unknown liquid. They used a buret to find a v
Daniel [21]

They should report the density as 1.11 g/L .

Density = mass/volume = 2.260g/2.04 mL

My calculator says the density <em>1.107 843 137 g/mL</em>

However, the answer can have <em>no more</em> significant figures than are in the number with the <em>fewest </em>significant figures.

The volume measurement has only three significant figures, so we must round off the density to three significant figures.

We drop all the digits after the zero.

The digit to be dropped is 7, so we <em>round up </em>the last significant figure of the answer.

1.10<u>7 843 137</u> → 1.11

4 0
4 years ago
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