This question is incomplete, the complete question is;
When an auditorium has a solid wall, sound waves will tend to perfectly reflect off the wall (i.e. with a 180o phase change). If listening to music, as from an orchestra, the incoming and reflected waves will interfere with each other. For a listener sitting 0.5 m from the wall, what is the lowest frequency which gets suppressed by this interference? Use vsound=330 m/s.
Answer: f = 165 Hz
the lowest frequency which gets suppressed by this interference is 165 Hz
Explanation:
For a reflected wave (out of phase), the path difference between the incoming and reflected wave should be equal to the half integral multiple of wavelength.
r₂ - r₁ = ( m + 1/2) λ/2
r₂ is the distance from the source to observer via reflection
r₁ is distance from source to observer
here r₂ would travel an additional distance of 0.5 m due to reflection that straight approaching wave.
Therefor to have minimum/lowest possible frequency, we say m = 0
we substitute
0.5 = ( 0 + 1/2 ) λ/2
λ = 2m
The frequency would be
f = Vsound / λ
f = 330 / 2
f = 165 Hz
Therefore the lowest frequency which gets suppressed by this interference is 165 Hz
Answer:
.A. positive, positive.
Explanation:
When we throw a rock upward , it will decelerate due to gravitation . It will have acceleration in downward direction or - ve acceleration in upward direction.
If we define the ground as the origin and upward direction as positive , anything in upward direction will be positive and in downward direction will be negative . For example , in the case described above , acceleration of rock thrown upward is negative because is in downward direction .
Its position is in upward direction , so its position is positive with respect to ground.
It is going in upward direction . So velocity too will be positive.
Answer:
dudududusjdudjjjjj*jdjdjdudhdudjdjfkrjfjrjfutf yifykryidistusisidyidyodyos6odtisotdkyslusydyi f70r6rv97t07t gxhztssitsuustsd6dyr6d6fuffyrurite9hibi ghseivifvgdiheduiebxhd9hxeoxhojdobrcbidicbeifbc rfviebf0jepjforbochrihciehco3fhiehfoehro3hfoho hcoh obfvobrjfo4heibdic. 4curbx. ei bb b ib iebib 3ih bibi bi brib eob iebo eh eib eh odd vuu dvud bidhdih dih 9h od ibcichechebcebceir b i rb rih ifbr ob dohr h0h ej0 h oh ej eu9 eig 3gi e9g 3ig3 ige ig 3gi eig3 ig3 ihc3ih3 hi3vhic3ohc3ho 3hov3ig3cho
Explanation:
ufssgkdyixgixgoxcucufighkdsisitsiyfryr6ruegsug3uvi3bsiebibs3ivj4vsusvibsibeksbl3sb2kbskb3skbsib2isbibsoh2zohsisnezigeucduebdub4sjbisegwjbiedbiedbxeibesibedibexuzevjexvuxevexuvexugexibexibez7x3i3xgu3xggzeizeguz3c3xuvzeugzi3g3uscz3yzefyezgu3xgixegiexbeigeiz3chzwcgezuvzeivzevudxbeix rurxgrxhkxebejxvjexbjexbxeideo besiz zozhekzekbzezibbhzzozozizoozozozoozozozozoozozozzozozizizizizizoozozozozozozozozozozozozoozozozozozoozozoozozozozozoozozozozozozoozozozozosozozoOzoozOoOOOOOoOzoozozooOOoOOOoOOOOOOkOOPkONiVhCcCTdyFuGigIhIfYfyDYsHfyFuGiHiH
Let's see
![\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20x%3DAsin%28%5Comega%20t%29%5Cdots%281%29)
Now we know the formula of acceleration
![\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Calpha%3D-A%5Comega%5E2sin%28%5Comega%20t%29)
![\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Calpha%3D-Asin%28%5Comega%20t%29%5Ctimes%20%5Comega%5E2)
![\\ \rm\Rrightarrow \alpha=-x\omega^2](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Calpha%3D-x%5Comega%5E2)
Or
![\\ \rm\Rrightarrow \alpha=-\omega^2x](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Calpha%3D-%5Comega%5E2x)