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Karolina [17]
3 years ago
15

Compare the catching of two different water balloons. Case A:​ A 600-mL water balloon moving at 8 m/s is caught and brought to a

stop. Case B:​ A 150-mL water balloon moving at 8 m/s is caught with the same technique and brought to a stop. The collision time is the same for each case. Which variable is different for these two cases?
Physics
2 answers:
Vadim26 [7]3 years ago
8 0

Answer:

jduruhrjrhryyrurjjrjrh4h5ghrrhrhhrhrhrhrrhrhrh sus

Explanation:

jdhshhehehehje

muminat3 years ago
5 0
It is case A, which you need to give an example about of it to get the answer .
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A boy is playing with a ball of mass 72g attached to a string. He is moving it at constant speed in a horizontal circle of radiu
irina [24]

Answer:

Explanation:

radius of circle r = 0.9 m.

(a ) In a motion on circular path , work done is zero because force ( centripetal force ) acts perpendicular to displacement .

( b )

Tension in string T = m ω²r

Putting the values

60 = .072 x ω² x 0.9

ω² = 926

ω = 30.4 rad /s

angle made in 20 revolutions θ = 20 x 2π = 126.6 rad

time taken = θ / ω

= 126.6 / 30.4

= 4.16 s .

3 0
3 years ago
Difine scalar quantity​
vfiekz [6]

Scalar quantity are physical quantities that have just magnitude, not direction.

  • It is always positive.
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8 0
3 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has—— energy. Calculate
Slav-nsk [51]

Answer:

945 j

Explanation:

You have just given the ball kinetic energy, which is given by the following equation:

KE= 1⁄2 m v2 = 1⁄2 (2.1 kg)(30 m/s)2 = 945 Joules

3 0
4 years ago
3 m/s north is an example of a(n) ____.
alexandr1967 [171]
Rate of speed (3 m/s north is three miles per second north, so it's a rate of speed)
4 0
3 years ago
Read 2 more answers
A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula
igomit [66]

Answer:

Angular acceleration of the disk will be \alpha =10.714rad/sec^2

Explanation:

We have given mass of the disk m = 5 kg

Diameter of the disk d = 30 cm = 0.3 m

So radius r=\frac{d}{2}=\frac{0.3}{2}=0.15m

Moment of inertia of disk is given by I=\frac{1}{2}mr^2=\frac{1}{2}\times 5\times 0.15^2=0.056kgm^2

Force is given by F=4 N

Torque is given as \tau =Fr=4\times 0.15=0.6N-m

We also know that torque is given by \tau =I\alpha

0.6=0.056\times \alpha

\alpha =10.714rad/sec^2

5 0
3 years ago
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