Answer:
See the answer and explanation below , please.
Explanation:
A conjugate base is defined as that formed after an acid donates its proton.
For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:
a) HF + H20 --> F- + H30+
b) H20+ H20 --> OH- + H30+
C)H2PO3- + H20--> HPO3 2- + H30+
d) HSO4- + H20 --> SO4 2- + H30+
E) HCL02 + H20 --> CLO02 - + H30+
The cubic unit cell this metal crystallize as is BCC structure .
<h3>
What is unit cell ?</h3>
The structure of a crystalline solid, whether a metal or not, is best described by considering its simplest repeating unit, which is referred to as its unit cell.
The unit cell consists of lattice points that represent the locations of atoms or ions.
The entire structure then consists of this unit cell repeating in three dimensions
n= 2
Hence our assumption was correct
It is a BCC structure .
Therefore the cubic unit cell this metal crystallize as is BCC structure .
To know more about unit cell
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Using a stove to heat up water.
Answer:
36.55kJ/mol
Explanation:
The heat of solution is the change in heat when the KNO3 dissolves in water:
KNO3(aq) → K+(aq) + NO3-(aq)
As the temperature decreases, the reaction is endothermic and the molar heat of solution is positive.
To solve the molar heat we need to find the moles of KNO3 dissolved and the change in heat as follows:
<em>Moles KNO3 -Molar mass: 101.1032g/mol-</em>
10.6g * (1mol/101.1032g) = 0.1048 moles KNO3
<em>Change in heat:</em>
q = m*S*ΔT
<em>Where q is heat in J,</em>
<em>m is the mass of the solution: 10.6g + 251.0g = 261.6g</em>
S is specififc heat of solution: 4.184J/g°C -Assuming is the same than pure water-
And ΔT is change in temperature: 25°C - 21.5°C = 3.5°C
q = 261.6g*4.184J/g°C*3.5°C
q = 3830.87J
<em>Molar heat of solution:</em>
3830.87J/0.1048 moles KNO3 =
36554J/mol =
<h3>36.55kJ/mol</h3>
<em />
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)
I’m going to assume 0 degrees Celsius.
At 0 C (273 K):
dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ
The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.
This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
