Question

Calculate the mass of gold(III) chloride Au2Cl6 that contains a billion 1.000x10^9 chlorine atoms.

Answer 1

Answer:

73.81 fg  

Explanation:

1. Calculate the number of Al₂Cl₆ molecules

$\text{No of molecules} =1.000 \times 10^{9}\text{ atoms Cl}\times \dfrac{\text{ 1 molecule Al _{2} Cl}_{6}}{\text{6 atoms Cl }}\\\\ =1.667 \times 10^{8} \text{ molecules Al _{2} Cl}_{6}$

2. Calculate the moles of Al₂Cl₆

$\text{No. of moles} = 1.667 \times 10^{8}\text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} =2.768 \times 10^{-16} \text{ mol}$

3. Calculate the mass of Al₂Cl₆

$\text{Mass} = 2.768 \times 10^{-16} \text{ mol} \times \dfrac{\text{266.68 g}}{\text{1 mol}} = 7.381 \times 10^{-14}\text{ g}= \textbf{73.81 fg}$