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viktelen [127]
3 years ago
15

What is the pressure of 2.0 mol nitrogen (N2) gas in a 0.5 L container at 310 K?

Chemistry
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

10.304 kPa

Explanation:

n=mol nitrogen (N2) gas=2moles

Temperature=T=310 K

Volume=0.5 L=0.5 dm3

R=8.31 J K−1 mol−1

From Gerenal gas equation we know that

PV=nRT

P=nRT/V

Putting the values

P=(2*8.31*3100/(0.5)

P=10.304 kPa

or P=10304 Pa

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For each process, predict the sign on the entropy change and write a sentence or two to explain how to make this prediction with
MrRa [10]

Answer: a. A solid melts: \Delta S=+ve

b. a vapor is converted to solid: \Delta S=-ve

c. a liquid freezes:  \Delta S=-ve

d. A solid sublimes:  \Delta S=+ve

e.  a vapor condenses to liquid :  \Delta S=-ve

f. a liquid boils:   \Delta S=+ve

g. dissolving a tablespoon of salt in water:  \Delta S=+ve

h. combustion of gasoline:  \Delta S=+ve

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy change is negative and vice versa.

a. A solid melts: The solid is converting to liquid, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

b. a vapor is converted to solid: The gas  is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger Thus the entropy change (\Delta S) is negative.

c. a liquid freezes: The liquid is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

d. A solid sublimes: The solid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

e.  a vapor condenses to liquid : The gas  is converting to liquid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

f. a liquid boils: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

g. dissolving a tablespoon of salt in water: The solid is converting to ions , thus the randomness is increasing as the ions can move freely. Thus the entropy change (\Delta S) is positive.

h. combustion of gasoline: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

6 0
2 years ago
What mass of silver oxide, Ag2O is required to produce 25.0 g of silver sulfadiazine, AgC10H9N4SO2, from the reaction of silver
Wittaler [7]

Answer:

8.1107 g

Explanation:

The given reaction:

2C_{10}H_{10}N_4SO_2+Ag_2O\rightarrow 2AgC_{10}H_9N_4SO_2+H_2O

Given that:

Mass of silver sulfadiazine = 25.0 g

Molar mass of silver sulfadiazine = 357.14 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{25.0\ g}{357.14\ g/mol}

Moles= 0.07\ mol

From the reaction,

2 moles of silver sulfadiazine are formed from 1 mole of silver oxide

So,

1 mole of silver sulfadiazine are formed from 1/2 mole of silver oxide

0.07 mole of silver sulfadiazine are formed from 1/2*0.07 mole of silver oxide

Moles of silver oxide = 0.035 moles

Molar mass  of silver oxide = 231.735 g/mol

Mass = Moles * Molar mass = 0.035 moles * 231.735 g/mol = 8.1107 g

4 0
3 years ago
The type of radioactive particle that can be stopped by a sheet of paper is the
koban [17]
Answer is alpha particles
5 0
3 years ago
Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en
Bezzdna [24]

Answer:

  • 10.19 g CO₂
  • 4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

  • C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:

  • 1 gallon = 3.785 L
  • 1 L = 1000 mL

Now we<u> convert 1.24 gallons to mL</u>:

  • 1.24 gallon * \frac{3.785L}{1gallon} *\frac{1000mL}{1L} = 4693.4 mL

We <u>calculate the mass of Octane</u>:

  • 4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:

  • CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * \frac{8molCO_{2}}{1molOctane} * 44 g/mol =  10.19 g CO₂
  • H₂O ⇒ 3.30 g Octane ÷ 114g/mol * \frac{9molH_{2}O}{1molOctane} * 18 g/mol = 4.69 g H₂O

7 0
3 years ago
Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
sergiy2304 [10]
The balanced chemical reaction is:

<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4  <span>( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3</span>
7 0
3 years ago
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