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meriva
3 years ago
5

If light gave off 7.17 x 10^17 of energy what is its wavelength?

Chemistry
1 answer:
professor190 [17]3 years ago
7 0

Answer:

,mhmh

Explanation:

hghfhfh

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In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?
Sauron [17]

Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

R_{eq}=R_1+R_2+....

For 17 light bulbs, the equivalent resistance is given by :

R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17

Hence, the total resistance is 17 ohms. Hence, the correct option is (d).

7 0
3 years ago
Which statement about electrons is not true?a. One electron state is a bonding orbital between nucleib. One electron state is an
NemiM [27]

Answer:

b. One electron state is an anti-bonding orbital, which results in an absence of electron density between atoms.

Explanation:

8 0
3 years ago
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0
1 year ago
Which of the following has a polar covalent bond? b. Which of the following has a bond closest to the ionic end of the bond spec
Marizza181 [45]

Explanation:

<u>Polar covalent bonding is the type of the chemical bond in which the pair of the electrons is unequally shared between the two atoms.</u> As a result, the atom with higher value of electronegativity acquires a slightly negative charge and the atom with lower value of electronegativity acquires a slightly positive charge.

In the molecule of CH_3NH_2, the bond which is closest to ionic end of bond spectrum is <u>N-H bond</u> because the nitrogen atom is more electronegative than hydrogen and is ionic in nature.

In the molecule of CH_3CH_3, the bond which is closest to ionic end of bond spectrum is <u>no one</u> because there is not much difference between carbon and hydrogen for the bond to be said as ionic.

In the molecule of CH_3OH, the bond which is closest to ionic end of bond spectrum is <u>O-H bond</u> because the oxygen atom is more electronegative than hydrogen and is ionic in nature.

5 0
3 years ago
Read 2 more answers
a graduated cylinder (approximate as a regular cylinder) has a radius of 1.045 cm and a height of 30.48 cm. what is the volume o
Luba_88 [7]

Answer: 103.5 cm^3

Explanation:

8 0
3 years ago
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