Air enters a compressor at a pressure of 74.7 kPa and 287 K and leaves at 622 kPa and 579 K. The air flow rate is 50 kg/s. Calcu
late the shaft power input required to drive the compressor. Hint: The shaft power that goes into the compressor increases the total enthalpy of the air from the inlet to the exit, since there is no heat into the system.
1 answer:
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Answer:
F₁ = 1500 N
F₂ = 750 N
= 500 N
Explanation:
Given :
Power transmission, P = 7.5 kW
= 7.5 x 1000 W
= 7500 W
Belt velocity, V = 10 m/s
F₁ = 2 F₂
Now we know from power transmission equation
P = ( F₁ - F₂ ) x V
7500 = ( F₁ - F₂ ) x 10
750 = F₁ - F₂
750 = 2 F₂ - F₂ ( ∵F₁ = 2 F₂ )
∴F₂ = 750 N
Now F₁ = 2 F₂
F₁ = 2 x F₂
F₁ = 2 x 750
F₁ = 1500 N , this is the maximum force.
Therefore we know,
= 3 x
where is centrifugal force
=
/ 3
= 1500 / 3
= 500 N