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3 years ago

Module 42 Review and Assessment

Engineering

1 answer:

Ivenika [448]3 years ago

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This is a lot of information but I just wanted to say I hope you have a great day!

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Carbon dioxide flows at a rate of 1.5 ft3 /s from a 3-in. pipe in which the pressure and temperature are 20 psi (gage) and 120 °

Monica [59]

Answer:

the absolute pressure in the smaller pipe = 19.63 psi

Explanation:

Let A be the diameter of the first pipe = 3 inches

Let B be the diameter of the second pipe. = 1.5 inches

To feet (ft) ; we have

Diameter of the pipe A $D_1 = (\dfrac{3}{12})ft = 0.25 \ ft$

Diameter of pipe B $D_1 = (\dfrac{1.5}{12})ft = 0.125 \ ft$

Temperature T = 120° F = (120+ 460)°R

= 580 ° R

The pressure gage to atmospheric pressure ; we have:

$P_{Absolute }=P _{Atm} + P_{guage}$

where;

atmospheric pressure = 1.47 psi

pressure gage = 20 psi

$P_{Absolute }=(1.47+20)psi$

$P_{Absolute }=34.7 \ psi$

To lb/ft²; we have:

$P_{Absolute }=(34.7 *144 ) lb/ft^2$

$P_{Absolute }=$ 4.998.6 fb/ft²

The density of carbon dioxide can be calculated by using the relation

$\rho = \dfrac{P}{RT}$

$\rho = \dfrac{4996.8}{(1130 \ lb /slug ^0 R)*(580{^0} R)}$

$\rho = 7.64*10^{-3}\ slug /ft^3$

Formula for calculating cross sectional area is

$A = \dfrac{\pi}{4}D$

For diameter of pipe $D_1 = 0.025$

A₁ = $\dfrac{\pi}{4}*0.25^2$

A₁ = 0.04909 ft²

For diameter of pipe $D_2 - 0.0125$

A₂ $=\dfrac{\pi}{4}*0.125^2$

A₂ = 0.012227 ft²

Using the continuity equation to determine the velocities V₁ and V₂ respectively.

For V₁

Q = A₁V₁

V₁ = Q₁/ A₁

V₁ = 1.5/0.04909

V₁ = 30.557 ft/s

For V₂

Q = A₂V₂

V₂= Q₂/ A₂

V₂ = 1.5/0.04909

V₂ = 30.557 ft/s

Finally; using Bernoulli's Equation to the flow of the carbon dioxide from the larger pipe to the smaller pipe ; we have:

$p_1 + \dfrac{\rho V_1^2}{2}+\gamma Z_1= p_2 + \dfrac{\rho V_2^2}{2}+\gamma Z_2$

Since the pipe is horizontal then;

$\gamma Z_1= \gamma Z_2$

So;

$p_1 + \dfrac{\rho V_1^2}{2}= p_2 + \dfrac{\rho V_2^2}{2}$

$p_2 =p_1 +\dfrac{1}{2} \rho(V_1^2-V_2^2)$

$p_2 =4996.8+\dfrac{1}{2} *7.624*10^{-3}(30.557^2-122.23^2)$

$p_2 =4943.41 \ lb/ft^2$

To psi;

$p_2 =\dfrac{4943.41 }{144}psi$

$p_2 =34.33 \ psi$ gage

The absolute pressure in the smaller pipe can be calculated as:

$p_2 _{absolute} = 34.33 - 14.7$

$p_2 _{absolute} = 19.63 \ \ absolute$

Hence, the absolute pressure in the smaller pipe = 19.63 psi

7 0

3 years ago

Which of the following technologies will the design and development of a bicycle stand be categorized under?

Yuri [45]

Answer:

when you're going to need a designer a builder an electrical builder and a mechanic and you're going to need to be careful with what you use for all those things but the bike need to build you'll need a structure

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2 years ago

A window‐mounted air‐conditioning unit (AC) removes energy by heat transfer from a room, and rejects energy by heat transfer to

Arada [10]

Solution :

Given :

The power of the air‐conditioning (AC) unit is , W = 0.434 kW

The coefficient of performance or the COP of the air‐conditioning (AC) unit is given by = 6.22

Therefore he heat removed is given by , $Q_H = 6.22 \times 0.434$

$Q_H = 2.7 \ kW$

Now if the electricity is valued at 0.10 dollar per kW hour, then the operating cost of the air conditioning unit in 24 hours is given by = 0.10 x 2.7 x 24

= 6.48

Therefore the operating cost = $ 6.48 for 24 hours.

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3 years ago

which of the following tools is used for measuring small diameter holes which a telescoping gauge cannot fit into? A. telescopin

Alex

Answer:

C. Dial indicator

Explanation:

This meassers small diameters

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2 years ago

To measure the greening of the U.S. economy, you need only to look at the growing number of green jobs and occupations.

puteri [66]

Answer is True.. hope I helped... pls mark brainliest

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3 years ago

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