so you can see all the different categories at once. both as a whole and on an individual scale.
Explanation:
Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the square of the orbital period (P).
For each of our planets orbiting the Sun, the relationship between the orbital period and semimajor axis can be represented by the equation as:
![P^2=kA^3](https://tex.z-dn.net/?f=P%5E2%3DkA%5E3)
k is constant of proportionality
It is required to solve the above equation for k
![k=\dfrac{P^2}{A^3}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7BP%5E2%7D%7BA%5E3%7D)
Underground, carbon can be stored in ____, which humans ___.
-----------------------------
coal, oil, fossil fuels ... humans burn for energy
Data:
![f_{2} = 42 Hz](https://tex.z-dn.net/?f=f_%7B2%7D%20%3D%2042%20Hz)
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
![f_{n} = \frac{nV}{2L}](https://tex.z-dn.net/?f=f_%7Bn%7D%20%3D%20%20%5Cfrac%7BnV%7D%7B2L%7D%20)
Wire 2 → 2º Harmonic → n = 2
![f_{n} = \frac{nV}{2L}](https://tex.z-dn.net/?f=f_%7Bn%7D%20%3D%20%5Cfrac%7BnV%7D%7B2L%7D%20)
![f_{2} = \frac{2V}{2L} ](https://tex.z-dn.net/?f=f_%7B2%7D%20%3D%20%5Cfrac%7B2V%7D%7B2L%7D%20%0A)
![2V = f_{2} *2L](https://tex.z-dn.net/?f=2V%20%3D%20%20f_%7B2%7D%20%2A2L)
![V = \frac{ f_{2}*2L }{2}](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B%20f_%7B2%7D%2A2L%20%7D%7B2%7D%20)
![V = \frac{42*2L}{2}](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B42%2A2L%7D%7B2%7D%20)
![V = \frac{84L}{2}](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B84L%7D%7B2%7D%20)
![V = 42L](https://tex.z-dn.net/?f=V%20%3D%2042L)
Wire 1 → 1º Harmonic or Fundamental rope → n = 1
![f_{n} = \frac{nV}{2L}](https://tex.z-dn.net/?f=f_%7Bn%7D%20%3D%20%5Cfrac%7BnV%7D%7B2L%7D%20)
![f_{1} = \frac{1V}{2L}](https://tex.z-dn.net/?f=f_%7B1%7D%20%3D%20%5Cfrac%7B1V%7D%7B2L%7D%20)
![f_{1} = \frac{V}{2L}](https://tex.z-dn.net/?f=f_%7B1%7D%20%3D%20%20%5Cfrac%7BV%7D%7B2L%7D%20)
If, We have:
V = 42L
Soon:
![f_{1} = \frac{V}{2L}](https://tex.z-dn.net/?f=f_%7B1%7D%20%3D%20%5Cfrac%7BV%7D%7B2L%7D%20)
![f_{1} = \frac{42L}{2L}](https://tex.z-dn.net/?f=f_%7B1%7D%20%3D%20%5Cfrac%7B42L%7D%7B2L%7D%20)
![\boxed{f_{1} = 21 Hz}](https://tex.z-dn.net/?f=%5Cboxed%7Bf_%7B1%7D%20%3D%2021%20Hz%7D)
Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
Can someone help me with a question? At the local ski park, James earns 519.36 for working 32 hours. Create a double number line to identify the amount of money he would make for 1, 8 and 40 hours of work?