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bulgar [2K]
3 years ago
5

A car starts from rest and accelerates for 5.2 s with an acceleration of 2.8 m/s 2 . How far does it travel? Answer in units of

m.
Physics
1 answer:
Mumz [18]3 years ago
5 0
The final velocity is 5.2^2. The initial velocity is 0 . You are using Kinematic equation 3. (V^2=Vo^2+2a(x)) . (5.2^2=2(2.8)x)
27.04=5.6x
27.04/5.6=5.6/5.6x
4.83=x
The answer is 4.83m:)
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20.0 -kg cannonball is fired from a cannon with muzzle speed of 1000m/s at an angle of 37.0° with the horizontal. A second ball
Dovator [93]

The mechanical energy for the first and the second ball is

10 ^{7}  \: joules.

Mass of the first ball = 20 kg

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 37°

The maximum height reached by the first ball is,

=   \frac{ u {}^{2} _{1}sin {}^{2} θ}{2g}

=    \frac{ {1000}^{2} sin {}^{2}37°}{2 \times 9.8}

= 18478.69 \: m

The maximum height of the first cannonball is 17478.69 m.

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 90 °

=   \frac{ u {}^{2} _{2}sin {}^{2} θ}{2g}

=   \frac{ 1000{}^{2}sin^{2} 90°}{2 \times 9.8}[tex] = 51020.41 \: m

For the first ball, total mechanical energy= Potential energy at maximum height + kinetic energy at the maximum height

So, the total mechanical energy is,

= mgh \: + \frac{1}{2}mv {}^{2} _{x}[/tex]

= 20 \times 9.8 \times 18478.64  \times  \frac{20}{2} (1000 \: cos37 °)

= 10 ^{7}  The potential energy at the maximum height, = m _{2}gh

= 20 \times 9.8  \times 51020.41

= 10 ^{7} \:J

Therefore, the total mechanical energy for the first and the

\:second \:  cannonball \:  is  \: 10 ^{7}  \:joules.

To know about energy, refer to the below link:

brainly.com/question/1932868

#SPJ4

5 0
2 years ago
A 20.0 F capacitor initially charged to 30.0 uC is discharged through a 3.00 k resistor. How long does it take to reduce the cap
Maslowich

Answer:

t = 0.04159 s

Explanation:

when a capacitor and resister are connected in series. charge on its plates decreases exponentially

q = qo * e^{\frac{-t}{RC}}

where,

CHARGE q  =15.0 C

INITIAL CHARGE q_0 = 30.0 uc

Resistor R = 20.0 F

capacitor C  = 3.00

15 = 30* e^{\frac{- t}{(20* 10^{-6} * 3* 1000)}

t = 0.04159 s

3 0
4 years ago
By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin
kodGreya [7K]
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
8 0
3 years ago
Read 2 more answers
Making payments to a victim in order to repay them for losses they incurred during or as a result of the crime is called
FrozenT [24]
<span>the answer is victim restitution</span>
3 0
3 years ago
There is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.
igor_vitrenko [27]
  • Mass=2kg
  • Velocity=40m/s

We know

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

  • m denotes to mass
  • v denotes to velocity

\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2

\\ \sf\longmapsto K.E=40^2

\\ \sf\longmapsto K.E=1600J

6 0
3 years ago
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