Answer:
a) The mass flow rate through the nozzle is 0.27 kg/s.
b) The exit area of the nozzle is 23.6 cm².
Explanation:
a) The mass flow rate through the nozzle can be calculated with the following equation:
Where:
: is the initial velocity = 20 m/s
: is the inlet area of the nozzle = 60 cm²
: is the density of entrance = 2.21 kg/m³
Hence, the mass flow rate through the nozzle is 0.27 kg/s.
b) The exit area of the nozzle can be found with the Continuity equation:
Therefore, the exit area of the nozzle is 23.6 cm².
I hope it helps you!
A. The vector goes from (4,0) to (3-2)
(x,y)
Answer:
D...............................
Answer:
A major problem in all survey research is that respondents are almost always self-selected. Not everyone who receives a survey is likely to answer it, no matter how many times they are reminded or what incentives are offered.
Explanation:
<em><u>DISADVANTAGES</u></em>
Respondents may not feel encouraged to provide accurate, honest answers.
Respondents may not feel comfortable providing answers that present themselves in a unfavorable manner.
Respondents may not be fully aware of their reasons for any given answer because of lack of memory on the subject, or even boredom.
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Answer:
Explanation:
Let the four resistances of th wheat stone bridge is
P, Q, R and S and the value of each is 350 ohm.
Here, P and Q are in series.
R' = P + Q = 350 + 350 = 700 ohm
Then R and S are in series
R' = R + S = 350 + 350 = 700 ohm
Now R' and R'' are in parallel.
So, the equivalent resistance is
Req = R' x R'' / ( R' + R'')
Req = 700 / 2 = 350 ohm
Thus, the reading of ohmmeter is 350 ohm.
