Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
![\omega=\dfrac{a_{max}}{v_{max}}](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7Ba_%7Bmax%7D%7D%7Bv_%7Bmax%7D%7D)
Put the value into the formula
![\omega=\dfrac{200}{2.0}](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B200%7D%7B2.0%7D)
![\omega=100\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D100%5C%20rad%2Fs)
We need to calculate the amplitude of the wave
Using formula of velocity
![v_{max}=A\omega](https://tex.z-dn.net/?f=v_%7Bmax%7D%3DA%5Comega)
![A=\dfrac{v_{max}}{\omega}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bv_%7Bmax%7D%7D%7B%5Comega%7D)
Put the value into the formula
![A=\dfrac{2.0}{100}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B2.0%7D%7B100%7D)
![A=0.02\ m](https://tex.z-dn.net/?f=A%3D0.02%5C%20m)
Hence, The amplitude of the wave is 0.02 m.
Answer:
This world shall know PAIN
Answer:
Explanation:
circulatory and digestive. ... An immune response is primarily due to the body's white blood cells recognizing.
Answer: 2
The hands need to be in direct contact with the flames to have conduction
Explanation:
A fire spreads by transferring heat energy in three ways: Radiation, Convection, and Conduction. Radiation by emitting energy in rays or waves. Heat moves through space as energy waves by conduction. As the fire front gets closer, the amount of radiant heat received is increased.
Heat energy in the form of electromagnetic radiation moves away from a hot object in all directions. Radiant heat is particularly important to fire development in a compartment in that it serves as one of the primary mechanisms for fire spread within the compartment.
<h2>
Answer:g=9.79
,A object of mass
![m](https://tex.z-dn.net/?f=m)
at the surface of earth experiences a force
![mg](https://tex.z-dn.net/?f=mg)
</h2>
Explanation:
Let
be the mass of earth.
Let
be the radius of earth.
Let
be the universal gravitational constant.
Given,
![M=5.96\times 10^{24}Kg](https://tex.z-dn.net/?f=M%3D5.96%5Ctimes%2010%5E%7B24%7DKg)
![R=6.37\times 10^{6}m](https://tex.z-dn.net/?f=R%3D6.37%5Ctimes%2010%5E%7B6%7Dm)
![G=6.67259 \times 10^{-11}](https://tex.z-dn.net/?f=G%3D6.67259%20%5Ctimes%2010%5E%7B-11%7D)
![Nm^{2}Kg^{-2}](https://tex.z-dn.net/?f=Nm%5E%7B2%7DKg%5E%7B-2%7D)
Let
be the acceleration due to gravity.
Then,![g=\dfrac{GM}{R^{2}}](https://tex.z-dn.net/?f=g%3D%5Cdfrac%7BGM%7D%7BR%5E%7B2%7D%7D)
![g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7B6.67259%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%205.96%5Ctimes%2010%5E%7B24%7D%7D%7B%286.37%5Ctimes%2010%5E%7B6%7D%29%5E%7B2%7D%7D)
![g=9.79ms^{-2}](https://tex.z-dn.net/?f=g%3D9.79ms%5E%7B-2%7D)
A object of mass
at the surface of earth experiences a force ![mg](https://tex.z-dn.net/?f=mg)