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Ierofanga [76]
3 years ago
9

If you are measuring how far a ball traveled in an experiment which example below could be an

Physics
1 answer:
Galina-37 [17]3 years ago
3 0
20 meters long because the b
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Suppose a proton ( = 1. 67×10^−27 kg) is confined to a box of width = 1. 00×10^−14 m (a typical nuclear radius).
dimulka [17.4K]

Answer:

22e837281949222324

Explanation:

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3 years ago
Which travels fastest through empty space? A. electromechanical waves B. transverse waves C. longitudinal waves D. electromagnet
Nady [450]
The answer is B hope it helps:)
7 0
3 years ago
If you pull a resistant puppy with its leash in a horizontal direction, it takes 80 N to get it going. You can then keep it movi
netineya [11]

Answer:

The coefficient of static friction between the puppy and the floor is 0.7273.

Explanation:

The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:

F_s = \mu_s*N

Where F_s is the static friction force, \mu_s is the coefficient of static friction and N is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, N = 110\text{ N}, to make the puppy moving we need to use a force of 80 N, therefore, F_s = 80 \text{ N}, so we can solve for the coefficient as shown below:

80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\

The coefficient of static friction between the puppy and the floor is 0.7273.

5 0
3 years ago
An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (cons
Nata [24]

Answer:

Dear Kaleb

Answer to your query is provided below

Acceleration of the vehicle is 12m/s^2

Explanation:

Explanation for the same is attached in image

8 0
3 years ago
Two particles of equal mass m are at the vertices of the base of an equilateral triangle. The triangle’s center of mass is midwa
Helga [31]

Answer:Twice of given mass

Explanation:

Given

Two Particles of Equal mass placed at the base of an equilateral Triangle

let mass of two equal masses be m and third mass be m'

Taking one of the masses at origin

Therefore co-ordinates of first mass be (0,0)

Co-ordinates of other equal mass is (a,0)

if a is the length of triangle

co-ordinates of final mass (\frac{a}{2},\frac{\sqrt{3}a}{2})

Given its center of mass is at midway between base and third vertex therefore

x_{cm},y_{cm}=\frac{a}{2},\frac{\sqrt{3}a}{4}

y_{cm}=\frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}

\frac{\sqrt{3}a}{4}=\frac{m\cdot 0+m\cdot 0+m'\cdot \frac{\sqrt{3}a}{2}}{m+m+m'}

2m+m'=4\times (\frac{m'}{2})

2m+m'=2m'

m'=2m

8 0
3 years ago
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