Answer:
i can't see it is to tinny so i don't know what to do
Step-by-step explanation:
Answer: 2/3 left and 1/3 used
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
67
Step-by-step explanation:
Subsitute both given values into the equation then continue to simplify the equation
3(4(-2)+5(3)) -2(7(-2)-3(3))
3(-8+15) -2(-14-9)
3(7) -2(-23)
21 +46
67
If you are trying to factor this problem then the answer is
2(v^3+7)^2