Question

As a dilligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.11-m-long rod as you jog at 3.07 m/s, holding the rod perpendicular to your direction of motion. What is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.287 mV across the rod

Answer 1

Answer:

The strength of the magnetic field is 0.0842 mT

Explanation:

Given:

Velocity of rod $v = 3.07$ $\frac{m}{s}$

Length of rod $l = 1.11$ m

Induced emf across the rod $\epsilon = 0.287 \times 10^{-3}$ V

According to the faraday's law

We have a special case for moving rod in magnetic field.

Induced emf in moving rod is given by,

   $\epsilon = Blv$

Where $B =$ strength of magnetic field

  $B = \frac{\epsilon}{lv}$

  $B = \frac{0.287 \times 10^{-3} }{3.07 \times 1.11}$

  $B = 0.0842 \times 10^{-3}$ T

  $B = 0.0842$ mT

Therefore, the strength of the magnetic field is 0.0842 mT