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weeeeeb [17]
4 years ago
9

In order to determine the power, you must know..

Physics
2 answers:
amm18124 years ago
8 0

Answer:

the right answer is...…..…..…..…..…..…

A. current and voltage

Explanation:

Rudik [331]4 years ago
6 0
Choices 'a' and 'd' will both do the job.
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An 92-kg football player traveling 5.0m/s in stopped in 10s by a tackler. What is the original kinetic energy of the player? Exp
Artemon [7]

Explanation:

It is given that,

Mass of the football player, m = 92 kg

Velocity of player, v = 5 m/s

Time taken, t = 10 s

(1) We need to find the original kinetic energy of the player. It is given by :

k=\dfrac{1}{2}mv^2

k=\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2

k = 1150  J

In two significant figure, k=1.2\times 10^3\ J

(2) We know that work done is equal to the change in kinetic energy. Work done per unit time is called power of the player. We need to find the average power required to stop him. So, his final velocity v = 0

i.e. P=\dfrac{W}{t}=\dfrac{\Delta K}{t}

P=\dfrac{\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2}{10\ s}

P = 115 watts

In two significant figures, P=1.2\times 10^2\ Watts

Hence, this is the required solution.  

6 0
3 years ago
How can three resistors of resistance 2ohm,3ohm and 6ohm be connected to go live total resistance of (a) 4ohm,(b)1ohm?​
Sophie [7]

\sf\large \green{\underbrace{\red{Answer⋆}}}:

(a) R2, R3 are parallel and series with R1

(b) R1, R2 and R3 are in parallel

Explanation:

\sf R_1 = 2  \: ohm\\  \sf R_2 = 3 \: ohm \\  \sf  R_3 = 6 \: ohm

(a)

\sf R_2   \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a

\sf  \large \frac{1}{R_a}  =  \frac{1}{R_2}  +  \frac{1}{R_3}  \: as \: they \: are \: in \: parallel

\sf R_a =  \frac{1}{3}  +  \frac{1}{6}  \\  \\  \sf  \frac{1}{R_a}  =  \frac{2 + 1}{6}  \\  \\  \sf \frac{1}{R_a}   =  \frac{3}{6}  \\  \\  \sf  \frac{1}{R_a}  =  \frac{1}{2}  \\  \\  \sf R_a = 2 \: ohm

Ra and R1 is in series

And there total will be R

\sf R = R_a + R_1 \\  \\  \sf R = 2 + 2 \\  \\  \sf R = 4 \: ohm

(b)

\sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R

\sf \frac{1}{R}  =  \frac{1}{R_1}  +  \frac{1}{R_2}  +  \frac{1}{R_3}  \\  \\   \sf   \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  +  \frac{1}{ 6}  \\  \\  \sf  \frac{1}{R}  =  \frac{3+ 2 +1 }{6}  \\  \\  \sf  \frac{1}{R}  =  \frac{6}{6}  \\  \\  \sf R = 1 \: ohm

8 0
2 years ago
After the scientist make a hypothesis, they perform an _______to collect data.
Lana71 [14]

Experiment

After the scientist make a hypothesis, they perform an experiment to collect data.

8 0
4 years ago
Which of the following statements about the force on a charged particle due to a magnetic field are not valid?
Ratling [72]

Answer:

this is from quizlet and is similar hope it helps.

Explanation:

Which of the following statements about the force on a charged particle due to a magnetic field are not valid?

Check all that apply.

a. It depends on the strength of the external magnetic field.

b. It depends on the particle's charge.

c. It depends on the particle's velocity.

d. It acts at right angles to the direction of the particle's motion.

e. None of the above; all of these statements are valid.

8 0
2 years ago
Find the magnitude of the electric field at a point 0.35 m to the right of a sphere of a charge of 1.20×10^−6 C.
frozen [14]

https://mrsstowell.weebly.com/uploads/5/1/4/6/51460659/hsav_riverdale.k12.wi.us_20160330_092123.pdf

6 0
3 years ago
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