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3 years ago

Find the magnitude of the electric field at a point 0.35 m to the right of a sphere of a charge of 1.20×10^−6 C.

Physics

1 answer:

frozen [14]3 years ago

6 0

https://mrsstowell.weebly.com/uploads/5/1/4/6/51460659/hsav_riverdale.k12.wi.us_20160330_092123.pdf

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The surface or material that underlies a two-dimensional work of art is called the ____.

Paul [167]

The surface or material that underlies a two-dimensional work of art is called the support.

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4 years ago

A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and

Natalka [10]

The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.

We don't have external forces, so:

$P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\$

Where:

mb is the mass of the bowling ball
mp the mass of the pin
$v_{0b}\quad and\quad v_{0p}$ the initial velocities of the bowling ball and the pin.
$v_{1b}\quad and\quad v_{1p}$ the final velocities of the bowling ball and the pin.

Solving for v0b:

$v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}$

<h2>R/ The original velocity of the ball was 5.71 m/s.</h2>

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3 years ago

If you're going 80 mph how long does it take to go 80 miles

Elza [17]

1 mile. Is this a joke lol

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4 years ago

Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24

scZoUnD [109]

Answer: 655.7 nm

Explanation:

Given

The slits are separated by $d=0.510\ mm$

Distance between slits and screen is $D=2.24\ m$

Adjacent bright fringes are $\beta =2.88\ mm$ apart

Also, the distance between bright fringes is given by

$\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm$

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3 years ago

Classify the following situations as involving balanced or unbalanced forces.

wariber [46]

Answer:

1. A. yeah but I'm not going anywhere else in

2. B. ugh I'm so happy for her and she

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3 years ago