before colliding the momentum of block A is -100 kg*m/s, and block B is -150 kg*m/s. after, block A has a momentum -200 kg*m/s.
1 answer:
The momentum of block B after the collision is -50 kg m/s.
Explanation:
We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system before and after the collision must be conserved, so we can write:
where:
is the momentum of block A before the collision
is the momentum of block B before the collision
is the momentum of block A after the collision
is the momentum of block B after the collision
Solving for , we find:
So, the momentum of block B after the collision is -50 kg m/s.
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Explanation:
Formula to determine the critical crack is as follows.
= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and,
= 427.5
Hence, we will calculate the critical crack length as follows.
a =
=
=
Therefore, largest size is as follows.
Largest size = 2a
=
=
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is .