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patriot [66]
3 years ago
15

If there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3500 m to an altitude of

400 m , where she will pull her ripcord?
Physics
1 answer:
xxMikexx [17]3 years ago
7 0

By equation of motion we have S = ut + 0.5 at^{2}

Where u = Initail velocity, S= dispalcement, t = time taken, a = acceleration

Here S = 3500-400 = 3100m, u = 0m/s, g = 9.8 m/s^{2}

So, 3100 = 0+0.5*9.8*t^{2}

       t^{2} = 3100/4.9

       t = \sqrt{3100/4.9}

      t = 25.15 seconds

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Which volcanic hazard can block the sunlight and temporarily cool the Earth’s surface?
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If a volcano epulses massive amounts of dust into the atmosphere, those two things will/can happen.
The events will last until the dust lays down on the earth.

8 0
3 years ago
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a small table has a mass of 4kg, stands on four legs, each leg having an area of 0.001 m2. what is the pressure exerted by the t
Gemiola [76]

Answer:

P = 10 kPa

Explanation:

Given that,

The mass of a small table, m = 4 kg

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We need to find the pressure exerted by the table on the floor. Pressure is equal to the force per unit area. So

P=\dfrac{mg}{4\times A}\\\\P=\dfrac{4\times 10}{4\times 0.001}\\P=10000\ Pa\\\\or\\\\P=10\ kPa

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3 0
3 years ago
Change.
solniwko [45]

Option E, Fiat money includes currency, checking deposits and credit cards .

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7 0
3 years ago
Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0
4 years ago
A point charge Q of mass M is located initially at the center of the ring. When it is displaced slightly, the point charge accel
dolphi86 [110]

Answer:

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Explanation:

6 0
4 years ago
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