3. The point where two rays meet to form an angle is called the

max2010maxim [7]

There are two opposite pairs and I am not sure if this is a select all question.
But here are the following:

B) C and F are pairs. That is -4 and 4
D) A and H are pairs. That is -8 and 8

Hope this helps!

3 0

3 years ago

Pentagon ABCDE was enlarged:

enot [183]

Answer/Step-by-step explanation:

The ratio of the enlargement to the original = A'E' to AE = A'E':AE = A'E'/AE

AE = 2.5

A'E' = 4

Ratio of the enlargement to the original = 4:2.5 = 1.6:1

To convert to percentage, divide 4 by 2.5 and multiply by 100.

$= \frac{4}{2.5}*100$

$= 1.6*100$

$= 160 percent$

7 0

3 years ago

15(x - 3) = 3 ( 2x - 3 ) 5

Lilit [14]

Answer:

15x - 45 = 6x -9

15x -6x = -9 + 45

9x = 36

x=27

Step-by-step explanation:

first you multiply the ones in the bracket by the front number .Then you group them ,after grouping because you want x to be on its own, so you divide the number in front of x by the common numbers standing alone .The answer you get will be your x .I hope my explanation helped .Thank you soo ... much.

7 0

3 years ago

Two tanks are interconnected. Tank A contains 60 grams of salt in 50 liters of water, and Tank B contains 80 grams of salt in 40

Illusion [34]

Let a(t) and b(t) denote the amounts of salt in tanks A and B, respectively.

The volume of liquid in tanks A and B after t minutes are

A: 50 L + (5 L/min + 3 L/min - 8 L/min)t = 50 L

B: 40 L + (7 L/min + 8 L/min - 3 L/min - 12 L/min)t = 40 L

so the amount of solution in the tanks stays constant.

Salt flows into tank A at a rate of

(2 g/L)*(5 L/min) + (b(t)/40 g/L)*(3 L/min) = (10 + 3/40 b(t)) g/min

and out at a rate of

(a(t)/50 g/L)*(8 L/min) = 4/25 a(t) g/min

so the net flow rate is given by the differential equation

$\dfrac{\mathrm da(t)}{\mathrm dt}=10+\dfrac{3b(t)}{40}-\dfrac{4a(t)}{25}$

We do the same for tank B: salt flows in at a rate of

(3 g/L)*(7 L/min) + (a(t)/50 g/L)*(8 L/min) = (21 + 4/25 a(t)) g/min

and out at a rate of

(b(t)/40 g/L)*(3 L/min + 12 L/min) = 3/8 b(t) g/min

and hence with a net rate of

$\dfrac{\mathrm db(t)}{\mathrm dt}=21+\dfrac{4a(t)}{25}-\dfrac{3b(t)}8$

Replace a(t) and b(t) with x and y. Then the system is (in matrix form)

$\dfrac{\mathrm d}{\mathrm dt}\begin{bmatrix}x\\y\end{bmatrix}=\dfrac1{200}\begin{bmatrix}-32&15\\32&-75\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}+\begin{bmatrix}10\\21\end{bmatrix}$

with initial conditions x(0) = 60 g and y(0) = 80 g.

7 0

3 years ago

At age 20, to save for retirement, Rebecca decides to deposit 80$ at the end of each month in an IRA that pays 6.2% compounde

artcher [175]

Answer:

159319.26 I Don't know the interest

7 0

3 years ago