Answer:
Long question good luck:)
Explanation:
Answer:
False.
Explanation:
The forces on the car and truck are equal and opposite. The equal forces cause accelerations of the truck and car inversely proportional to their mass. That is, If the Truck A exerts a force FAB on car B, then the car will exert a force FBA on the truck. Therefore,
FBA = −FAB
However, this can be explained by Newton's second law. Let's say the truck has mass M and the car has mass m. If the magnitude of the force that both vehicles experience is F, then the magnitudes of their respective accelerations are:
atruck = F/M
acar = F/m
and combining these we get:
atruck/acar = m/M
So if the mass of the car is a lot less than the mass of the truck, then the acceleration of the truck is much smaller than the acceleration of the car, and if you were to watch the collision, the truck would pretty much seem like it's motion was unaffected, but the car's motion will change quite a bit.
Answer:
A large area of a forest will likely have higher biodiversity than a smaller area of the same forest.
A half acre of rainforest would likely have greater biodiversity than a full acre of desert.
Explanation:
biodiversity of an ecosystem can be simply explain as the variability that exist in the ecosystem. These are difference that exist between living organism in terms of their habitat, their species and so on. However there exist different relationship between the area of ecosystem and the biodiversity of an ecosystem such that An ecosystem with large area of a forest will likely have higher biodiversity than a smaller area of the same forest.
Another one is that A half acre of rainforest would likely have greater biodiversity than a full acre of desert.
Answer:
Δ
= 84 Ω,
= (40 ± 8) 10¹ Ω
Explanation:
The formula for parallel equivalent resistance is
1 /
= ∑ 1 / Ri
In our case we use a resistance of each
R₁ = 500 ± 50 Ω
R₂ = 2000 ± 5%
This percentage equals
0.05 = ΔR₂ / R₂
ΔR₂ = 0.05 R₂
ΔR₂ = 0.05 2000 = 100 Ω
We write the resistance
R₂ = 2000 ± 100 Ω
We apply the initial formula
1 /
= 1 / R₁ + 1 / R₂
1 /
= 1/500 + 1/2000 = 0.0025
= 400 Ω
Let's look for the error (uncertainly) of Re
= R₁R₂ / (R₁ + R₂)
R’= R₁ + R₂
= R₁R₂ / R’
Let's look for the uncertainty of this equation
Δ
/
= ΔR₁ / R₁ + ΔR₂ / R₂ + ΔR’/ R’
The uncertainty of a sum is
ΔR’= ΔR₁ + ΔR₂
We substitute the values
Δ
/ 400 = 50/500 + 100/2000 + (50 +100) / (500 + 2000)
Δ
/ 400 = 0.1 + 0.05 + 0.06
Δ
= 0.21 400
Δ
= 84 Ω
Let's write the resistance value with the correct significant figures
= (40 ± 8) 10¹ Ω