Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3
Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3
= 1010 kg/m^3
Answer:
1) 1.15 mol
2) M=0.45
3) 22.5 mL
4) 6.25 mL
Explanation:
1)
550 mL= 0.55 L
M= mol solute/ L solution
mol solute= M * L solution
mol solute= (2.1 M * 0.55 L ) M=1.15 mol solute
2)
155 mL = 0.155 L
80 g -> 1 mol NH4NO3
5.61 g -> x
x= (5.61 g * 1 mol NH4NO3)/80 g x= 0.07 mol NH4NO3
M=(0.07 mol NH4NO3)/0.155 L M=0.45
3) M1V1=M2V2
V1= M2V2/M1
V1= (0.500 M * 0.225 L)/5.00 M V1=0.0225 L =22.5 mL
4) M1V1=M2V2
V1= M2V2/M1
V1= (0.25 M * 0.45 L)/ 18.0 M
V1=6.25 x 10^-3 L = 6.25 mL
Answer:
Explanation:
The correct measurement is .710 s which is equal to .71 s so second measurement that is 0.71 s is most accurate measurement .
B. 0.71s is the most accurate .
Precision depends upon measuring instrument . Measurement by highly precise instrument has greater precision .
The measurement of 0.75 ± 0.002s must have been taken from high precise instrument because it is capable of making measurement upto 3 decimal points .
Hence
C 0.75 ± 0.002s is most precise measurement .
That is a chemical change.. Hope I helped!
Answer:
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
Explanation:
The equation used to calculate the constant for first order kinetics:
.....(1)
Rate law expression for first order kinetics is given by the equation:
![t=\frac{2.303}{k}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
......(2)
where,
k = rate constant
=Half life of the reaction = 
t = time taken for decay process = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the reactant = 0.163 M
[A] = amount left after time t = 66.8% of
[A]=
t = 1,409.19 s
1 minute = 60 sec
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
