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geniusboy [140]
3 years ago
8

Bonds between two atoms that are equally electronegative are _____. bonds between two atoms that are equally electronegative are

_____. ionic bonds hydrogen bonds nonpolar covalent bonds polar covalent bonds
Chemistry
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

Non-polar covalent  bond.

Explanation:

Ionic bond:It is that type of bond which is formed by gain or loss of electrons between two atoms.

Hydrogen bond:It is that type of bond in which hydrogen atom is linked with atom of high electronegativity.

Polar covalent bond: It is formed by sharing of electrons of electrons between two atoms of different electronegativity.

Non-Polar covalent bond:It is formed by sharing of electrons between two atoms of same electronegativity.

Bond between two atoms that are equally  electronegative are non-polar covalent bond.

DanielleElmas [232]3 years ago
7 0
Bonds between two atoms that are equally electronegative are nonpolar covalent bonds
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Evgen [1.6K]

Answer:

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Keq= [Mg3P2]/[Mg]^3 [P]^2

Explanation:

The equation for the formation of magnesium phosphide from its elements is;

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Hence we can see that three moles of magnesium atoms combines with two moles of phosphorus atoms to yield one mole of magnesium phosphide. The equation written above is the balanced chemical reaction equation for the formation of the magnesium phosphide.

The equilibrium expression for the reaction K(eq) will be given by;

Keq= [Mg3P2]/[Mg]^3 [P]^2

8 0
3 years ago
Can anyone please help me!! What is d. Beat the eggs?? A physical or a chemical change?
Stells [14]

Answer:

physical change

Explanation:

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6 0
3 years ago
What is the product of the unbalanced equation below?
Stolb23 [73]

Answer:

D

Explanation:

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3 0
3 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
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nika2105 [10]
Answer is: cesium sulfide.
Formula for ionic compound is: Cs₂S.
Ionic compound <span>electrically </span>neutral, cesium has charge +1 (2· (+1) = +2) and sulfur has charge -2.
Cesium sulfide is whide powder, soluble in water, pyrophoric in dry air, reductant.
5 0
3 years ago
Read 2 more answers
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