Answer:
D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
Explanation:
Step 1: Detemine the mass of O in SO₂
There are 2 atoms of O in 1 molecule of SO₂. Then,
m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g
Step 2: Determine the mass of SO₂
m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g
Step 3: Detemine the mass percent of oxygen in SO₂
We will use the following expression.
m(O)/m(SO₂) × 100%
(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
Answer:
-608KJ/mol
Explanation:
3 C2H2(g) -> C6H6(g)
ΔHrxn = ΔHproduct - ΔHreactant
ΔHrxn= ΔHC6H6 - 3ΔHC2H2
ΔHrxn = 83 - 3(230)
ΔHrxn = -608
Hi!
The generic equation showing how a weak base ionizes water is the following:
B(aq) + H₂O(l) ⇄ BH⁺(aq) + OH⁻(aq)
A base is described as weak when its dissociation is difficult and isn't complete. Weak Bases are chemical compounds that accept protons from water, to form the conjugate acid and the OH⁻ ion. The pH of the solution of a weak base is higher than 7. Some weak bases include ammonia (NH₃), Aluminum Hydroxide (Al(OH)₃) and Sodium Acetate (CH₃COONa).
Have a nice day!
The chemical formula is
composed of hydrogen and oxygen where the two atoms are bonded through hydrogen
bond type of bonding. In this pair, the oxygen is the more electronegative atom
hence the electrons are more directed to it. Because of this, this creates
electron polarity which affects the chemical property of water.
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