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Natalka [10]
3 years ago
14

Thomas records the masses of several rocks as 7.40 g, 7.85 g, 7.60 g, and 7.40 g. What is the mode of Thomas’s data set?

Physics
1 answer:
slamgirl [31]3 years ago
4 0
Mode = 7.40 g

[ As it is repeating here ]

Hope this helps!
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A 900 kg car moves around a 500 m radius curve at 25.0 m/s. What is the centripetal force on
Gnesinka [82]

Answer:

9375 N

Explanation:

From the question,

Centripetal force (F) = mv²/r.................. Equation 1

Where m = mass of the car, v = velocity of the car, r = radius of the curve.

Given: m = 900 kg, r = 600 m, v = 25 m/s

Substitute these values into equation 1

F = (900×25²)/600

F = 9375 N.

Hence the centripetal force on the car is 9375 N

3 0
2 years ago
The Earth's electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC a
castortr0y [4]

Answer:

The final kinetic energy is  K =  1.1 \ J

Explanation:

From the question we are told that

    The electric field is  E =  100 \ V/m

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    The mass of the object is  m_o  =  68 \ g  = 0.68 \ kg

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The workdone on the object by the fields  is  mathematically represented as

   W =  [qE + mg]d

Now this workdone is equivalent to the final kinetic energy so  

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substituting values

        K = W =  [4.5*10^{-3  } *100  + 0.68 * 9.8]* 1

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8 0
3 years ago
Please please help me out I’m lost
disa [49]

Answer:

Option B

The correct answer is 2

3 0
3 years ago
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Norma-Jean [14]

Answer:

Now e is due to the ring at a

So

We say

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So

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Finally we get the total

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So the direction here is away from the ring

8 0
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Harman [31]
Because it is intact and unfractured
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