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lara [203]
3 years ago
12

What is the mechanical advantage of a wedge that is 2 inches at its widest part and has a sloped side with a length of 10 inches

?
0.2
5
8
20
Physics
2 answers:
vichka [17]3 years ago
8 0

Answer: 5

Explanation:

The mechanical advantage of a wedge is given by the formula:

MA=\frac{L}{h}

where L is the length of the slope and h is the height.

In this problem, we have a length of L=10 inches and a height of h=2 inches, so the mechanical advantage is

MA=\frac{10}{2}=5

Delicious77 [7]3 years ago
7 0
The correct answer would be 5 hope this helps.
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weathering

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Which best describes why Keplers observation of planetary motion is a law instead of a theory
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Kepler's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks. Then tie the string into a loop and wrap the loop around the two tacks. Take your pencil and pull the string until the pencil and two tacks make a triangle (see diagram at the right). Then begin to trace out a path with the pencil, keeping the string wrapped tightly around the tacks. The resulting shape will be an ellipse. An ellipse is a special curve in which the sum of the distances from every point on the curve to two other points is a constant. The two other points (represented here by the tack locations) are known as the foci of the ellipse. The closer together that these points are, the more closely that the ellipse resembles the shape of a circle. In fact, a circle is the special case of an ellipse in which the two foci are at the same location. Kepler's first law is rather simple - all planets orbit the sun in a path that resembles an ellipse, with the sun being located at one of the foci of that ellipse.


5 0
3 years ago
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A cylinder of mass 14.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed o
aev [14]

Answer:

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b) 283.5J

c)850.5J

Explanation:

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E_r = \frac{1}{2} mv^2

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9m/s for v

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E_R = \frac{1}{2} Iw^2

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I = \frac{1}{2} mr^2

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w = \frac{v}{r}

substitute

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and vr for w

in equation for rotational kinetic energy as follows:

E_R = (\frac{1}{2}) (\frac{1}{2} mr^2)(\frac{v}{r} )^2

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The rotational kinetic energy of the center of mass is 283.5J

(c)

The expression for the total energy is,

E = E_r + E_R\\\\

substitute 567J for E(r) and 283.5J for E(R)

E = 567J + 283.5\\= 850.5J

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algol [13]

Answer:

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