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2 years ago

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What are the first three harmonics of a note produced on a 0.31 m long violin string if the waves on this string have a speed of

274.4 M/s. what is the length of the pipe

1 answer:

bezimeni [28]2 years ago

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Help please due tomorrow

Anni [7]

Hope this helps!!!!

6 0

3 years ago

A model railroad train travels at a constant speed of 8 cm/s . How far would the train travel in one minute ?

Furkat [3]

Answer:

Answer:

480cm or 0.48m

Explanation:

Given parameter:

Speed of the train = 8cm/s

time of travel = 1minute

Unknown:

Distance traveled = ?

Solution:

Speed is the rate of change of distance with time. This suggests that mathematically;

Speed =

Distance covered = speed x time

Now to solve for the distance;

Convert the time to seconds;

60seconds = 1 minute

Distance covered = 8cm/s x 60s = 480cm

Distance covered is 480cm or 0.48m

7 0

3 years ago

What property of a wave remains unchanged when a wave enters a different medium? 5 points amplitude frequency wavelength velocit

ASHA 777 [7]

Answer:

Frequency

Explanation:

The property of waves that remains unchanged as it crosses the boundary of one medium to another is the frequency of the wave.

As a wave moves from one boundary to another, the wavelength and the speed of the wave changes.

The speed of the wave is product of wavelength and frequency. Also, the wavelength of the wave is function of the distance between successive crests or troughs of a wave.

The frequency of a wave is the number of waves that crosses a medium per unit of time.

8 0

2 years ago

Find the distance separating two dust particles (in m) if each has a charge of +e and the Coulomb force between them has magnitu

marta [7]

Answer:

Distance between dust particles, $r=1.2\times 10^{-7}\ m$

Explanation:

Given that,

Charge on the dust particle, $q_1=q_2=1.6\times 10^{-19}\ C$

Force between dust particles, $F=1.6\times 10^{-14}\ N$

We need to find the distance between two dust particles. The electrostatic force between dust particles is given by :

$F=k\dfrac{q_1q_2}{r^2}$ , r = the distance

$r=\sqrt{k\dfrac{q_1q_2}{F}}$

$r=\sqrt{9\times 10^9\times \dfrac{(1.6\times 10^{-19})^2}{1.6\times 10^{-14}}}$

$r=1.2\times 10^{-7}\ m$

So, the distance between two dust particles is $1.2\times 10^{-7}\ m$ . Hence, this is the required solution.

7 0

3 years ago

a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration

olasank [31]

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Here's the solution :

Let's find the final velocity :

$\dfrac{displacement}{time}$

$\dfrac{80}{10}$

$8 \: \: ms {}^{ - 1}$

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

$acceleration = \dfrac{v - u}{t}$

$\dfrac{8 - 0}{10}$

$\dfrac{8}{10}$

$0.8 \: \: m {s}^{ - 2}$

Acceleration = 0.8 m/s²

7 0

3 years ago