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Sergio039 [100]
4 years ago
8

if the input force on a wheel and axle is 2 N and the output force is 20N what is its mechanical advantage

Physics
1 answer:
Nezavi [6.7K]4 years ago
5 0

Mechanical Advantage is always (Output Force) / (Input Force) .

MA = (20 N) / (2 N)

<em>MA = 10</em>

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Which of these chemical equations demonstrates the law of conservation of mass as it applies to the combustion of ethane? A. 2 C
WINSTONCH [101]

A. 2 C₂ H₆ + 7 O₂ → 4 C O₂ + 6 H₂ O


according to law of conservation of mass , the total mass of reactants side must be same as the total mass of product side. so we need to check if each atom in the equation has same number on both side of the equation or not.

in this equation , we have

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3 0
4 years ago
A hoop is rolling without slipping along a horizontal surface with a forward speed of 5.50 m/s when it starts up a ramp that mak
Burka [1]

Answer:

v_f = 4.22 m/s

Explanation:

As we know by energy conservation

initial total energy = final total energy

so we have

\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = \frac{1}{2}mv_f^2 + \frac{1}{2}I\omega_f^2 + mgL sin\theta

so we have

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I = mR^2

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5.50^2 = v_f^2 + (9.81)(3) sin25

30.25 - 12.43 = v_f^2

v_f = 4.22 m/s

5 0
4 years ago
Two moles of an ideal gas are compressed in a cylinder at a constant temperature of 80.0 ∘c until the original pressure has trip
elena55 [62]
The work done by a gas during an isothermal process is given by:
W=nRT ln \frac{V_f}{V_i} (1)
where
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
\frac{V_f}{V_i} is the ratio between the final volume and the initial volume of the gas

We need to calculate this ratio, and we can do it by using the gas pressure. In fact, for an isothermal process, Boyle's law states that the product between pressure and volume of the gas is constant:
pV=k
which can be rewritten as
p_i V_i= p_f V_f
which is equivalent to
\frac{V_f}{V_i}= \frac{p_i}{p_f}
The problem says that the pressure of the gas is tripled, therefore the ratio between final and initial volume is:
\frac{V_f}{V_i} = \frac{p_i}{3 p_i} = \frac{1}{3}

Now we can use eq.(1) to calculate the work done by the gas. The absolute temperature is
T=80.0^{\circ}C+273 = 353 K
The number of moles is n=2, therefore the work done is
W=nRT ln  \frac{V_f}{V_i}=(2 mol)(8.31 J/mol K) (353 K) \ln  \frac{1}{3}= -6445 J
And the work is negative, because it is done by the environment on the gas (the gas is compressed)

6 0
3 years ago
A 1610 kg car is traveling east at 22. m/s and a 3100. kg minivan traveling west at a speed of 11.0 m/s
Schach [20]

Answer:

Im pretty sure its 11 m/s east because it is 22 m/s hitting 11 m/s and the force is harder hitting

Explanation:

im not 100% sure becasue i did this stuff a while ago

8 0
3 years ago
What is the speed of light in air (n=1.0001)
omeli [17]
If the index of refraction of air is 1.0001, then the speed of light in air
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That's (299,792,458 m/s / 1.0001) = 299,762,481.8 m/s .
4 0
4 years ago
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