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Sergio039 [100]
3 years ago
8

if the input force on a wheel and axle is 2 N and the output force is 20N what is its mechanical advantage

Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Mechanical Advantage is always (Output Force) / (Input Force) .

MA = (20 N) / (2 N)

<em>MA = 10</em>

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AleksandrR [38]
Refer to the diagram shown.

Because the surface is frictionless, the resistive for, R, is zero.

Let m = the mass of the object.
Let a =  acceleration due to the applied force.
Therefore
12.7 N = (m kg)*(a m/s²)
a = 12.7/m  m/s²

The object travels  16.1 m in 2.5 s, starting from rest. Therefore
16.1 N = (1/2)*(12.7/m m/s²)*(2.5 s)² = 39.6875/m  N
m = 16.1/39.6875 = 0.4057 kg

For freefall, let g =  acceleration due to gravity.
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3 0
3 years ago
What is the kinetic energy of a 10kg object that is moving with a speed of 60m/s.
Sergio039 [100]

The answer is 18000 J

I hope this helps!^^ , if you need the work to be shown please tell me, I hope you have a great day!^^

5 0
2 years ago
1. Two forces act on a box as follows: F= 100 N at 02 = 170. and F2= 75 N at
Setler [38]

Answer:

yfv.

Explanation:

7 0
2 years ago
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
o-na [289]

Answer:

Current = 10 Amperes.

Explanation:

Given the following dat;

Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C

Time = 1 hour to seconds = 60*60 = 3600 seconds

To find the current;

Quantity of charge = current * time

Substituting in the equation

36000 = current * 3600

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6 0
2 years ago
The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second
just olya [345]

Answer:

g=274\ m/s^2

Explanation:

Mass of the Sun, M=1.99\times 10^{30}\ kg

The radius of the Sun, r=6.96\times 10^8\ m

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So, the value of acceleration due to gravity on the Sun is 274\ m/s^2.

8 0
2 years ago
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