Answer:
1.129×10⁻⁵ N
1.295 m
Explanation:
Take right to be positive. Sum of forces on the 31.8 kg mass:
∑F = GM₁m / r₁² − GM₂m / r₂²
∑F = G (M₁ − M₂) m / r²
∑F = (6.672×10⁻¹¹ N kg²/m²) (516 kg − 207 kg) (31.8 kg) / (0.482 m / 2)²
∑F = 1.129×10⁻⁵ N
Repeating the same steps, but this time ∑F = 0 and we're solving for r.
∑F = GM₁m / r₁² − GM₂m / r₂²
0 = GM₁m / r₁² − GM₂m / r₂²
GM₁m / r₁² = GM₂m / r₂²
M₁ / r₁² = M₂ / r₂²
516 / r² = 207 / (0.482 − r)²
516 (0.482 − r)² = 207 r²
516 (0.232 − 0.964 r + r²) = 207 r²
119.9 − 497.4 r + 516 r² = 207 r²
119.9 − 497.4 r + 309 r² = 0
r = 0.295 or 1.315
r can't be greater than 0.482, so r = 0.295 m.
Answer:
The magnitude of force is 1593.4N
Explanation:
The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as
fcostheta + Nsintheta = mv^2/r
Where F = force of friction
Theta = angle of banking
N = normal force
m = mass of car
v = velocity of car
r = radius of curve
The car has no motion in the vertical direction so the sum of forces = 0
The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.
Taking the upward direction to be positive,rewrite the equation above to get:
Ncos thetha = mg - fsintheta =0
Ncistheta = mg + fain theta
N = mg/cos theta + sintheta/ costheta
fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r
Substituting gives:
f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)
Substituting given values into the above equation
f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan
f = 1593.4N25
You would have to place your sensor above earth's atmosphere because it blocks out nearly all x-rays. this is why we have the Chandra observatory
hope this helps
Answer:
c. 
Explanation:
= Initial distance between asteroid and rock = 7514 km = 7514000 m
= Final distance between asteroid and rock = 2823 km = 2823000 m
= Initial speed of rock = 136 ms⁻¹
= Final speed of rock = 392 ms⁻¹
= mass of the rock
= mass of the asteroid
Using conservation of energy
Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy
