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Neko [114]
3 years ago
11

A transformer supplies 60 watts of power to a device that is rated at 20 volts. The primary coil is connected to a 120-volt ac s

ource. What is the current I1 in the primary coil
Physics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

I = 0.5 A

Explanation:

Given: P=60 Watts, Voltage supply V = 120 Volts (for primary coil)

Solution:

we have P = V I

⇒ I = P /V = 60 Watts / 120 Volts

I = 0.5 A

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A firecracker breaks up into two pieces , one has a mass of 200 g and files off along the x –axis with a speed of 82.0 m/s and t
Readme [11.4K]

Answer:

A) 21.2 kg.m/s at 39.5 degrees from the x-axis

Explanation:

Mass of the smaller piece = 200g = 200/1000 = 0.2 kg

Mass of the bigger piece = 300g = 300/1000 = 0.3 kg

Velocity of the small piece = 82 m/s

Velocity of the bigger piece = 45 m/s

Final momentum of smaller piece = 0.2 × 82 = 16.4 kg.m/s

Final momentum of bigger piece = 0.3 × 45 = 13.5 kg.m/s

since they acted at 90oc to each other (x and y axis) and also momentum is vector quantity; then we can use Pythagoras theorems

Resultant momentum² = 16.4² + 13.5² = 451.21

Resultant momentum = √451.21 = 21.2 kg.m/s at angle 39.5 degrees to the x-axis  ( tan^-1 (13.5 / 16.4)

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3 years ago
The diagram shows particles that make up an atom. Which label best completes the diagram?
KonstantinChe [14]
The right answer is "Strong nuclear force"
8 0
3 years ago
How does the study of social sciences affect our society?
Kruka [31]

Explanation:

study of social sciencake us an effcient citizen of a democracy ,and it also help us to solve the practical problem in our daily life.

8 0
3 years ago
The gravitational force between two objects that are 2.1 times 10^-1 m apart is 3.2 times 10^-6 N. If the mass of one object is
Shtirlitz [24]

Answer:

Mass of the other object is 38.45 kg.

Explanation:

Given:

The gravitational force between two objects is, F=3.2\times 10^{-6} N

Mass of one object is, m_{1}=55\ kg

Distance between the objects is, r=2.1\times 10^{-1}\ m

Gravitational constant is, G =6.674\times 10^{-11}\ m^3 kg^{-1}s^{-2}

Let the mass of the other object be m_{2}\ kg

Gravitational force is given as:

F=\frac{Gm_1m_2}{r^2}

Plug in the given values and solve for m_2. This gives,

3.2\times 10^{-6}=\frac{6.674\times 10^{-11}\times 55\times m_2}{(2.1\times 10^{-1})^2}\\3.2\times 10^{-6}=\frac{6.674\times 10^{-11}\times 55\times m_2}{0.0441}\\3.2\times 10^{-6}=8.3236\times 10^{-8}m_2\\m_2=\frac{3.2\times 10^{-6}}{8.3236\times 10^{-8}}= 38.45\ kg

Therefore, the mass of the other object is 38.45 kg.

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4 years ago
Which science will
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