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user100 [1]
3 years ago
11

Match the each term with its definition. 1) reaction coordinate a) the higher point on the energy curve 2) δg° b) the plot of th

e reaction progress as a function of time 3) δg‡ c) the free energy of the reaction
Chemistry
1 answer:
Vilka [71]3 years ago
4 0
The correct answer is:
1) reaction coordinate will match with
B)the plot of the reaction progress as a function of time.

as the reaction coordinate is the progress of a reaction from the reactants to products with different transition states in between. The X-axis: which has the reaction progress reflects the progressive chemical changes and the formation of bond and the bond breakage as S (the energy associated with the reactant) is changing and converting to P ( the energy that associated with the product).Actually, it has no relation to time.Rather partially formation of bonds and breaking of bond reaction steps.

2)ΔG° will match with  
c) the free energy of the reaction.

As it is simply defined as the Gibbs free energy and is also known as a free enthalpy, it is used to calculate the maximum of reversible work performed by the thermodynamic system when the temperature and the pressure are constant.

3)ΔG will match with
A) the higher point of the energy curve.

when ΔG = ΔGproduct - ΔGreactant
and It is simply defined as the change in free energy. It reflects nothing about the speed of the reaction. ΔG+ indicates that the reaction is endergonic and energy goes from reactants to products.and ΔG- become negative when the reaction goes to a lower energy state and it indicates then that the reaction is exergonic.

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7 0
3 years ago
The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?
n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of atmosphere = 5.00\times 10^{18}kg=5.00\times 10^{21}g

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = \frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol

Moles of carbon dioxide in air = \frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol

Hence, the moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

6 0
3 years ago
hurry please! avogadro's law relates the volume of a gas to the number of moles of gas when temperature and pressure are constan
DIA [1.3K]

Answer:

Option B. 4 moles of the gaseous product

Explanation:

Data obtained from the question include:

Initial volume (V1) = V

Initial number of mole (n1) = 2 moles

Final volume (V2) = 2V

Final number of mole (n2) =..?

Applying the Avogadro's law equation, we can obtain the number of mole of the gaseous product as follow:

V1/n1 = V2/n2

V/2 = 2V/n2

Cross multiply

V x n2 = 2 x 2V

Divide both side by V

n2 = (2 x 2V)/V

n2 = 2 x 2

n2 = 4 moles

Therefore, 4 moles of the gaseous product were produced.

5 0
3 years ago
Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
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<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
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3 years ago
Our wine is consisted of 12% v/v alcohol. How much a man of alcohol are consistent in 4 L of Wine
Zina [86]

Answer:

0.48

Explanation:

all you need is to decide 12% with 100% then you multiply it by 4L.

4 0
3 years ago
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