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Andrej [43]
2 years ago
5

You have an unknown compound of Potassium derivatives (KIxOy). This sample contains 17.0g of potassium, and 27.8g of oxygen and

55.2g of iodine. If you prepared another sample, but this time it had 460.0g of potassium periodate, how much oxygen and iodine would you have in your sample?
Chemistry
1 answer:
Alex777 [14]2 years ago
7 0

Answer:

The body temperatures in degrees Fahrenheit of a sample of adults in onle small town are 96.6 99.6 96. 3 97.3 99.8 97.7 97,6 97.9 99.2 Assume body temperatures of adults are normally distributed Based on this data find the 9900 confidence Interval of the mean body temperature of adults in the town Enter Your answer as an Open-interval (i.e. parentheses) accurate to 3 decimal places. Assume the data is from normally distributed population_ 9900 CI = Previewv Tp Enter 4euleie er using intewval notation. Example: [2,5) Uge U fcr unicr to combine interval:, Example: (-00,2] U [4,00} Entet each Faluce nunber (like 33,2.2172) Or 33 calculztion (like 5/3,243 5-4) Enter DNE for ar empty set, Use 00 to enter Infinity. Enter each valze accurate to decial place: Get Help: Points possible: 10 This attempt of 3 Me ye ingtmctor absutthis questin Poelis quesivto 6 EpIC e 6 DeA

Explanation:

(Unsure if this helped but hope it did!)

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Imagine a chemist is in the lab and trying to make some chemical reactions happen. In one reaction she reacts chemicals in an exothermic reaction and there is an increase in entropy. A second chemical reaction she is trying to run is endothermic and there is a decrease in entropy. Which of the two reactions is more likely to occur and why?

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CaC2(s) + 2H2O(l) --&gt; Ca(OH)2(aq) + C2H2(g) In the reaction above, 0.5487 grams of calcium carbide are completely consumed to
jasenka [17]

Answer:

239.7mL

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

The balanced chemical equation in this question is as follows:

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g)

From the equation, 1 mole of CaC2 produces 1 mole of ethylene gas, C2H2.

Using mole = mass/molar mass

Molar mass of CaC2 = 40 + 12(2)

= 40 + 24

= 64g/mol

mole = 0.5487/64

mole = 0.00857mol of CaC2

Hence, 0.00857mol of CaC2 produced 0.00857mol of C2H2

Based on the information provided, n = 0.00857mol, T = 43°C = 43 + 273 = 316K, p = 0.926 atm

PV = nRT

V = nRT/P

V = 0.00857 × 0.0821 × 316/0.926

V = 0.222/0.926

V = 0.2397L

In mL, volume = 0.2397 × 1000

= 239.7mL

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3 years ago
Which of the following elements is not likely to form bonds?
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I don’t understand the question
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