The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as
molar mass=33.29g
<h3>What mass of
krypton tetrachloride can be
produced assuming 100% yield?</h3>
Generally, the equation for ideal gas is mathematically given as
PV=nRT
Therefore
n=(0.50)(15.)/0.082*623
n=0.147mol
Hence for clorine
n=0.441mol
Given the reaction
Kr+2cl2---->KrCL4
Hence
molar mass=225.60*0.147
molar mass=33.29g
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Answer:
control.
Explanation:
during an experiment you are required to maintain a separate group of subjects to collect data on so you will be able to make comparisons from your observations. assuming the watered plants grew, what does that mean? they grew at a quicker rate? slower rate? the same rate? compared to what? you need this control group in order to prove your observations either one way or the other such as "compared to unwatered plants, the watered plants grew at *blank* rate."
The volume of the gas at STP = 35.01 L
<h3>Further explanation</h3>
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure).
In general, the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
V=17.4 L
T = 23 + 273 = 296 K
P = 2.18 atm
The volume of the gas occupy at STP :
Answer:
A, B, C
Explanation:
Notice that this reaction involves double arrows, meaning this represents an equilibrium reaction in which we observe a forward reaction (combination of hemoglobin and oxygen) and a reverse reaction (decomposition of the oxyhemoglobin complex).
Upon inhalation of oxygen, it accesses the blood of a person and binds to hemoglobin, so the following reaction proceeds to the right.
Similarly, the opposite process takes place in muscles, oxyhemoglobin is decomposed back into hemoglobin and oxygen.
The equilibrium constant reaction is relatively high, since at standard conditions, this is a spontaneous reaction, hemoglobin combines with oxygen without any additional external source of energy.
Answer:
The answer to your question is AgCl
Explanation:
Data
Silver = Ag = 75%
Chlorine = Cl = 25%
1.- Convert percent numbers to grams
Silver = 75 g
Chlorine = 25 g
2.- Calculate the moles of each element
Mass number Ag = 108 g
Mass number Cl = 35.5 g
108 g of Ag ------------------ 1 mol
75 g of Ag ------------------ x
x = (75 x 1) / 108
x = 75 / 108
x = 0.69 moles
35.5 g of Cl ------------------ 1 mol
25 g of Cl ----------------- x
x = (25 x 1) / 35.5
x = 0.70 moles
3.- Divide by the lowest number of moles
Ag = 0.69/0.69 = 1
Cl = 0.70 / 0.69 = 1.02 ≈ 1
4.- Write the empirical formula
Ag₁ Cl₁ = AgCl
