Question

Tin has many possible isotopes three of these isotopes are 114sn, 118sn, and 126sn. What’s the mass number in each? How many protons neutrons and electrons are present in each?

Answer 1

Explanation:

Tin is the 50th element of the periodic table and has many isotopes. Three of its isotopes are given which are: $_{50}^{114}\textrm{Sn}\text{ , }_{50}^{118}\textrm{Sn}\text{ and }_{50}^{126}\textrm{Sn}$

General representation of an isotope is $_Z^A\textrm{X}$

where,

A = atomic mass of the element

Z = atomic number of the element

X = symbol of the element

Atomic number is equal to the number of electrons or number of protons.

Atomic number = Number of electrons = Number of protons

Mass number is defined as the sum of number of neutrons and protons.

Mass number = number of protons + number of neutrons

• For Isotope $_{50}^{114}\textrm{Sn}$

Atomic number = number of electrons = number of protons = 50

Mass number = 114

Number of neutrons = 114 - 50 = 64

• For Isotope $_{50}^{118}\textrm{Sn}$

Atomic number = number of electrons = number of protons = 50

Mass number = 118

Number of neutrons = 118 - 50 = 68

• For Isotope $_{50}^{126}\textrm{Sn}$

Atomic number = number of electrons = number of protons = 50

Mass number = 126

Number of neutrons = 126 - 50 = 76