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4 years ago

Ann is driving down a street at 61 km/h.

Physics

1 answer:

Wittaler [7]4 years ago

4 0

Answer:

12.267 seconds approximately.

Explanation:

The units can be simplified into m/s, in which case you would have 61000/3600. Simplify that to 16 and 17/18. This is your meters per second, so multiply that by .724 to get the answer.

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What is the accletation of a 1500kg with a net force of 7500 N

matrenka [14]

Acceleration formulae is:
a=Fnet/mass
According to the question
a=7500N/1500kg
a=5m/s sq.

3 0

3 years ago

Learning Goal: To understand the concepts explaining the operation of transformers.

Alex

Answer:

Part a)

ZERO

Part b)

N = 10 turns

Explanation:

Part a)

As we know that transformer is used to change the input voltage into required output voltage

Here this input and output is considered only when it will change with time as the whole concept is based upon Faraday's law where we need to change the flux with time.

So if we have input Source is DC source then output voltage will be zero as there is no flux change

Part b)

As we know by the principle of transformer

$\frac{V_1}{V_2} = \frac{N_1}{N_2}$

$\frac{500}{25} = \frac{200}{N_2}$

$N_2 = 10$

so total number of turns in secondary coil must be 10

3 0

3 years ago

Doug is driving a golf ball off the tee. His downswing takes 0.50sec from the top of the swing until ball impact. At the top of

Dmitry [639]

D.eeeeeeezzzzzzzz nuuuuutttttssss!

6 0

3 years ago

An arch is in the shape of a parabola with its vertex at the top. It has a span of 100 feet and a maximum height of 40 feet. Fin

nexus9112 [7]

Answer:36.4 ft

Explanation:

Given

Span of Parabola $L=100 ft$

Maximum height $h=40$

suppose Parabola is of type

$(x-x_0)^2=-4a(y-y_0)$

where $x_0,y_0$ is the center of parabola

$x_0=0, y_0=40$

$x^2=-4a(y-40)$

at $y=0$

$x^2=-4a\times (-40)$

$x^2=160a$

$x=\pm \sqrt{160a}$

and it is given, $2x=100$

$x=50$

$\sqrt{160a}=50$

$a=15.625$

thus $x^2=-4a(y-40)$

at $x=15$

$15^2=-4\times 15.625(y-40)$

$y=36.4 ft$

4 0

3 years ago

A child in a boat throws a 5.80-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 24.6kg and the ma

Sergio [31]

Answer:

-0.912 m/s

Explanation:

When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

$(m_c + m_b)v_b + m_pv_p = 0$

where $m_c = 24.6 kg, m_b = 39 kg, m_p = 5.8 kg$ are the mass of the child, the boat and the package, respectively. $, v_p = 10m/s, v_b$ are the velocity of the package and the boat after throwing.

$(24.6 + 39)v_b + 5.8*10 = 0$

$63.6v_b + 58 = 0$

$v_b = -58/63.6 = -0.912 m/s$

3 0

4 years ago