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4 years ago

Ann is driving down a street at 61 km/h.

Physics

1 answer:

Wittaler [7]4 years ago

4 0

Answer:

12.267 seconds approximately.

Explanation:

The units can be simplified into m/s, in which case you would have 61000/3600. Simplify that to 16 and 17/18. This is your meters per second, so multiply that by .724 to get the answer.

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What best describes the relationship between the frequency of an oscillation and the period of the oscillation?

ZanzabumX [31]

Explanation:

Let f is the frequency of an oscillation and T is the period of the oscillation. There exists an inverse relationship between the frequency and the time period of the oscillation. Mathematically, it is given by :

$f=\dfrac{1}{T}$

Also, $f=\dfrac{\omega}{2\pi}$

So,

$T=\dfrac{2\pi}{\omega}$

The time taken to complete one oscillation is called the period of the oscillation and the number of oscillation is called the frequency if an oscillation.

4 0

3 years ago

(TCO 5) The relationship between Celsius (º C) and Fahrenheit (º F) degree of measuring temperature is linear. Find the linear e

gtnhenbr [62]

Answer:

$C=-\dfrac{10}{17}(F-32)$

Explanation:

Given that

32° F corresponds to 0 °C. ---Point 1

212° F corresponds to 100 °C.----Point 2

We know that if two point is given that equation of line can be found as

$y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)$

Lets C in y- direction and F in x- direction,so we can say that

$C-C_1=\dfrac{C_2-C_1}{F_2-F_2}(F-F_1)$

$C-0=\dfrac{100-0}{32-212}(F-32)$

$C=-\dfrac{10}{17}(F-32)$

So the linear relationship is

$C=-\dfrac{10}{17}(F-32)$

8 0

3 years ago

A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin

Musya8 [376]

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude y at time t is

$y(t)=50\,\mathrm m-\dfrac12gt^2$

where g = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when y = 0:

$0 = 50\,\mathrm m-\dfrac12gt^2$

$t^2=\dfrac{100\,\mathrm m}g$

$t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}$

6 0

3 years ago

Which of the following statements is true of chords? Select all that apply.

tankabanditka [31]

All of those are true, except the one about the radius.

Both ends of a chord have to be on the circle, but one end
of a radius is at the center, so a radius can't be a chord.

5 0

3 years ago

What is the ohms law

Anton [14]

The Ohm's law is I(the strength of the current flowing in a conductor)= V(the potential difference applied to the ends) divided by R(resistance)

4 0

3 years ago