The X and Y components of the force are 90.63 Newton and 42.26 Newton respectively.
<u>Given the following data:</u>
- Angle of inclination = 25°
To determine the X and Y components of the force:
<h3>The horizontal component (X) of a force:</h3>
Mathematically, the horizontal component of a force is given by this formula:
![F_x = Fcos \theta\\\\F_x =100 \times cos25\\\\F_x =100 \times 0.9063](https://tex.z-dn.net/?f=F_x%20%3D%20Fcos%20%5Ctheta%5C%5C%5C%5CF_x%20%3D100%20%5Ctimes%20cos25%5C%5C%5C%5CF_x%20%3D100%20%5Ctimes%200.9063)
Fx = 90.63 Newton.
<h3>The vertical component (Y) of tensional force:</h3>
Mathematically, the vertical component of a force is given by this formula:
![F_y = Fsin \theta\\\\F_y =100 \times sin25\\\\F_y =100 \times 0.4226](https://tex.z-dn.net/?f=F_y%20%3D%20Fsin%20%5Ctheta%5C%5C%5C%5CF_y%20%3D100%20%5Ctimes%20sin25%5C%5C%5C%5CF_y%20%3D100%20%5Ctimes%200.4226)
Fy = 42.26 Newton.
Read more on horizontal component here: brainly.com/question/4080400
Answer:
F_g = 372.78 N
Explanation:
Formula for force of gravity is;
F_g = mg
Where;
m is mass
g is acceleration due to gravity
We are given;
Mass = 38 kg
Acceleration due to gravity has a constant value of 9.81 m/s²
Thus;
F_g = 38 × 9.81
F_g = 372.78 N
Answer
Maximum speed at 75 m radius will be 22.625 m /sec
Explanation:
We have given radius of the curve r = 150 m
Maximum speed ![v_{max}=32m/sec](https://tex.z-dn.net/?f=v_%7Bmax%7D%3D32m%2Fsec)
Coefficient of friction ![\mu =\frac{v_{max}^2}{rg}=\frac{32^2}{150\times 9.8}=0.6965](https://tex.z-dn.net/?f=%5Cmu%20%3D%5Cfrac%7Bv_%7Bmax%7D%5E2%7D%7Brg%7D%3D%5Cfrac%7B32%5E2%7D%7B150%5Ctimes%209.8%7D%3D0.6965)
Now new radius r = 75 m
So maximum speed at new radius ![v_{max}=\sqrt{\mu rg}=\sqrt{0.6965\times 75\times 9.8}=22.625m/sec](https://tex.z-dn.net/?f=v_%7Bmax%7D%3D%5Csqrt%7B%5Cmu%20rg%7D%3D%5Csqrt%7B0.6965%5Ctimes%2075%5Ctimes%209.8%7D%3D22.625m%2Fsec)