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Usimov [2.4K]
2 years ago
10

What force controls the isostatic adjustment of Earth’s crust?

Physics
2 answers:
Alina [70]2 years ago
6 0
The force that control the isostatic adjustment of the earth's crust is THE FORCE OF GRAVITY.
The isostatic adjustment of the earth crust refers to continuous movement of the earth crust or its deformation as a result of the force of gravity which act on it. The earth crusts that are located at the upper and a the core of the earth usually set up a balance between them which is called isostatic equilibrium.
nirvana33 [79]2 years ago
6 0

Answer:

Gravity

Explanation:

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A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme
Lerok [7]

The density of the substance is<u> 10.5 g/cm³.</u>

The jewelry is made out of <u>Silver.</u>

Density ρ is defined as the ratio of mass <em>m</em> of the substance to its volume V<em>. </em> The cylinder contains a volume <em>V₁ of water</em> and when the jewelry is immersed in it, the total volume of water and the jewelry is found to be V₂.

The volume <em>V</em> of the jewelry is given by,

V=V_2 -V_1

Substitute 48.6 ml for <em>V₁ </em>and 61.2 ml for V₂.

V=V_2 -V_1\\ =61.2 ml -48.6 ml\\ =12.6 ml

calculate the density ρ of the jewelry using the expression,

\rho =\frac{m}{V}

Substitute 132.6 g for <em>m</em> and 12.6 ml for <em>V</em>.

\rho =\frac{m}{V}\\ =\frac{132.6 g}{12.6 ml} \\ =10.5 g/ml

Since 1 ml=1 cm^3,

The density of the jewelry is <u> 10.5 g/cm³.</u>

From standard tables, it can be seen that the substance used to make the jewelry is <u>silver</u><em><u>, </u></em>which has a density 10.5 g/cm³.



4 0
3 years ago
If the index of refraction of a lens is 1.5, how fast does light travel in the lens?
Len [333]
The speed of light in a material is given by:
v= \frac{c}{n}
where
c=3 \cdot 10^8 m/s is the speed of light in vacuum
n is the refractive index of the material

The lens in this problem has a refractive index of n=1.50, therefore the speed of light in the lens is
v= \frac{c}{n}= \frac{3 \cdot 10^8 m/s}{1.50}=2 \cdot 10^8 m/s

And the correct answer is C).
5 0
2 years ago
Read 2 more answers
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

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3 0
3 years ago
What us the formula of finding diameter
Over [174]

Answer:

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Explanation:

5 0
3 years ago
6)An electric field of 6 N/C points in the positive X direction. What is the electric flux through a surface that is 4 m2, if it
Salsk061 [2.6K]

Answer:

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Explanation:

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Electric filed vector, E = 6 i N/C

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\overrightarrow{A} = 4 (cos30 \widehat{i} + sin 30 \widehat{j})\\\\\overrightarrow{A} = 3.5 \widehat{i} + 2 \widehat{j}\\

The flux is given by

\phi= \overrightarrow{E}.\overrightarrow{A}\\\\\phi = 6 \widehat{i} .  \left (3.5 \widehat{i} + 2 \widehat{j}  \right )\\\\\phi = 21 Nm^2/C

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