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Andrews [41]
3 years ago
10

A push on a textbook with 10 N moves it to a distance of 2 cm. How much force is need to move it to 4 cm?

Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

20N

Explanation:

Ratio of N to cm-

10:2

so to make 2=4 times 2 so The ratio is now-

20:4

so to move 4 cm you need to push 20N.

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5 0
3 years ago
A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
3 years ago
a goalkeeper catches a 491 g soccer ball traveling horizontally at 29.4 m/s. if it took 2,218 n of force to stop the ball, how m
yarga [219]

The ball will take 2.551 seconds to reach its peak position.

<h3>How much time will the ball take to land?</h3>

We must know how long the balls are in the air before we can predict where they will fall. It will take 2 seconds for both balls to touch the ground.

<h3>How quickly does a ball drop?</h3>

The falling ball travels a distance of d = 12 9.8 (m/s2) t2, with a speed of v = 9.8 (m/s2) t as a function of time. The ball travels 4.9 m in a second. The falling ball's velocity is v = -9.8 (m/s2) t j, and its position is r = (4.9 m - 12 9.8 (m/s2) t2) j as a function of time.

To know more about balls visit:-

brainly.com/question/19930452

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6 0
1 year ago
Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the spe
erik [133]

Answer:

yes with a lot of time it eventualy could be, but in short term no

Explanation:

4 0
2 years ago
Calculate the gravitational potential energy of a 1200 kg car at the top of a hill that is 42 m high.
GalinKa [24]
It IS <span>PE = (1200 kg)(9.8 m/s²)(42 m) = 493,920 J </span>
6 0
3 years ago
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