Answer:
Explanation:
- For diagram refer the attachment.
It is given that five cells of 2V are connected in series, so total voltage of the battery:
![\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5C%3A%20%5C%3A%20%20%5Csf%20V%20%3D%202%20%5Ctimes%205%20%3D%20%3Cstrong%3E10%20V%3C%2Fstrong%3E%20)
Three resistor of 5
, 10
, 15
are connected in Series, so the net resistance:
![\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5C%3A%20%5C%3A%20%5Csf%20R_%7Bn%7D%20%3D%20R_%7B1%7D%20%2B%20R_%7B2%7D%20%2B%20R_%7B3%7D)
![\dashrightarrow \: \: \sf R = 5 + 10 + 15](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5C%3A%20%5C%3A%20%20%5Csf%20R%20%3D%205%20%2B%2010%20%2B%2015%20)
![{ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}](https://tex.z-dn.net/?f=%7B%20%5Cpink%7B%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%7B%20%5Cunderbrace%7BR%20%3D%2030%20%5C%3A%20%20%5COmega%7D%7D%7D%7D)
According to ohm's law:
![\dashrightarrow \sf\: \: V = IR](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%20%5Csf%5C%3A%20%5C%3A%20V%20%3D%20IR%20)
![\dashrightarrow \sf \: \: I = \dfrac{V}{R}](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%20%5Csf%20%5C%3A%20%5C%3A%20I%20%3D%20%5Cdfrac%7BV%7D%7BR%7D)
On substituting resultant voltage (V) as 10 V and resultant resistant, as 30
we get:
![\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20I%20%3D%20%5Cdfrac%7B10V%7D%7B30%5COmega%7D)
![{ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}](https://tex.z-dn.net/?f=%7B%20%5Cpink%7B%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%7B%20%5Cunderbrace%7BI%20%3D%200.33%20A%7D%7D%7D%7D)
The electric current passing through the above circuit when the key is closed will be <u>0.33 A</u>
To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.
By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation
![\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))](https://tex.z-dn.net/?f=%5CPhi%20%3D%202%5Cpi%28%5Cfrac%7BL%7D%7B%5Clambda%7D%28n_1-n_2%29%29)
Where
L = Thickness
n = Index of refraction of each material
Wavelength
Our values are given as
![\Phi = 7(2\pi)](https://tex.z-dn.net/?f=%5CPhi%20%3D%207%282%5Cpi%29)
![L=t](https://tex.z-dn.net/?f=L%3Dt)
![n_1 = 1.58](https://tex.z-dn.net/?f=n_1%20%3D%201.58)
![n_2 = 1](https://tex.z-dn.net/?f=n_2%20%3D%201)
![\lambda = 550nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%20550nm)
Replacing our values at the previous equation we have
![\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))](https://tex.z-dn.net/?f=%5CPhi%20%3D%202%5Cpi%28%5Cfrac%7BL%7D%7B%5Clambda%7D%28n_1-n_2%29%29)
![7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))](https://tex.z-dn.net/?f=7%282%5Cpi%29%20%3D%202%5Cpi%28%5Cfrac%7Bt%7D%7B%5Clambda%7D%281.58-1%29%29)
![t = \frac{7*550}{1.58-1}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B7%2A550%7D%7B1.58-1%7D)
![t = 6637.931nm \approx 6.64\mu m](https://tex.z-dn.net/?f=t%20%3D%206637.931nm%20%5Capprox%206.64%5Cmu%20m)
Therefore the thickness of the mica is 6.64μm
Radiator. A radiator puts warm air out at the top and draws in cooler air at the bottom. steaming cup of hot tea - The steam you see when drinking a cup of hot tea indicates that heat is being transferred into the air. ice melting/Ice melts because heat moves to the ice from the air
Answer:
it's false coz
Speed is a scalar quantity.