Answer:
0.4778 m/s
Explanation:
To solve this question, we will make use of law of conservation of momentum.
We are given that the rock's velocity is 12 m/s at 35°. Thus, the horizontal component of this velocity is;
V_x = (12 m/s)(cos(35°)) = 9.83 m/s.
Thus, the horizontal component of the rock's momentum is;
(3.5 kg)(9.83 m/s) = 34.405 kg·m/s.
Since the person is not pushed up off the ice or down into it, his momentum will have no vertical component and so his momentum will have the same magnitude as the horizontal component of the rock's momentum.
Thus, to get the person's speed, we know that; momentum = mass x velocity
Mass of person = 72 kg and we have momentum as 34.405 kg·m/s
Thus;
34.405 = 72 x velocity
Velocity = 34.405/72
Velocity = 0.4778 m/s
Answer:
correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons
Explanation:
No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels
Answer:
F = 400 N
Explanation:
Given,
The acceleration of the car, a = 8 m/s²
The mass of the passenger, m = 50 Kg
The force acting on a body is equal to the product of the mass and its acceleration
F = m x a newtons
Substituting the given values in the above equation,
F = 50 Kg x 8 m/s²
= 400 N
Hence, the force exerted by the person on the seat belt is, F = 400 N
