A beaker of boiling water stops boiling and eventually reaches room

A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t

rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

The velocity of the car is:

v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

$v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt$

v_ave = v0+a(T/2)

We can esaily note that when t=T/2

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

$x(t) = x_A + v_0 t + \frac{1}{2}at^2$

Where x_A is the position of point A. Therefore, the car will be at:

x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2

8 0

2 years ago

Jared is reading an article about the heavy rains that have fallen recently in his town. But he can’t separate the facts from th

Crank

FACTS:
|
|
It’s that time of year again when the days are wet and cool.
 The rainy season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
 and precipitation occur in the form of rain.
 Precipitation in the form of rain is better than snow.
 Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.

OPINIONS:
|
| It’s that time of year again when the days are wet and cool.
The rainy season is the best season.
 Rain makes up part of Earth’s water cycle.
 Water evaporates from streams, lakes, and oceans, then condensation
and precipitation occur in the form of rain.
Precipitation in the form of rain is better than snow.
Snow this time of year makes people gloomy.
 Rain is a great boon to local farmers.
 It helps their crops grow.

6 0

3 years ago

Read 2 more answers

If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?

sdas [7]

Data:
$f_{2} = 42 Hz$
n (Wave node)
V (Wave belly)
L (Wave length)
The number of bells is equal to the number of the harmonic emitted by the string.

$f_{n} = \frac{nV}{2L}$

Wire 2 → 2º Harmonic → n = 2

$f_{n} = \frac{nV}{2L}$
$f_{2} = \frac{2V}{2L} 
$
$2V = f_{2} *2L$
$V = \frac{ f_{2}*2L }{2}$
$V = \frac{42*2L}{2}$
$V = \frac{84L}{2}$
$V = 42L$

Wire 1 → 1º Harmonic or Fundamental rope → n = 1

$f_{n} = \frac{nV}{2L}$
$f_{1} = \frac{1V}{2L}$
$f_{1} = \frac{V}{2L}$

If, We have:
V = 42L
Soon:
$f_{1} = \frac{V}{2L}$
$f_{1} = \frac{42L}{2L}$
$\boxed{f_{1} = 21 Hz}$

Answer:

The fundamental frequency of the string:
21 Hz

7 0

3 years ago

Read 2 more answers

Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave r

Iteru [2.4K]

Answer:

$1.63\cdot 10^{-24} J$