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sveticcg [70]
4 years ago
8

Activities2. Write the balanced half-reactions of thecompound, CaF2​

Chemistry
2 answers:
Naily [24]4 years ago
7 0
Ur bot smart mate get a brain matr
boyakko [2]4 years ago
5 0
The answer is c . explanation c makes the most logical sense. it explains more in the question .
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Exactly 1.5 g of a fuel burns under conditions of constant pressure and then again under conditions of constant volume. In measu
nata0808 [166]

Answer:

Process B : constant pressure condition

Process A : constant volume condition

Explanation:

In case of constant pressure, some of the energy is used to do work on the surrounding to keep pressure constant. Due to this, the total heat energy is less than in case of constant volume. In Case of constant Volume all of heat is available, produced in reaction because no work is done.

If we look at our data,we will find that process B has energy 23.3 KJ which is less than process A, the energy of which is 25.9 KJ. It means Process B is occurred at constant pressure condition and Process A has occurred at constant volume condition

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4 years ago
What is the difference between 5.0 and 5.00??
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3 years ago
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What is the latent heat of vaporization?
Ksivusya [100]

Answer:

option B

Explanation:

<h3>The energy required to go from liquid to gas / water vapour</h3>
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3 years ago
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Please Help! Let P and V represent the pressure and volume of Xe(g). If a piston is used to reduce the volume of the gas to V/2
Elza [17]

1) 2P

2) Average speed does not change

Explanation:

1)

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

pV=const.

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

p_1 V_1 = p_2 V_2

where:

p_1 = P is the initial pressure

V_1=V is the initial volume

V_2=\frac{V}{2} is the final volume

Solving for p2, we find the final pressure:

p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P

So, the pressure has doubled.

2)

The average speed of the atoms/molecules in the gas is given by the formula

v_{rms}=\sqrt{\frac{3RT}{M}}

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

v_{rms} is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

8 0
4 years ago
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