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3 years ago

A throat lozenge contains 5.0 mg of menthol, which has the formula c10h20o.

1 answer:

5 0

A)
the molecular formula of menthol is C₁₀H₂₀O
molar mass of menthol is (12x10) + (1x20) + 16 = 156 g/mol
number of moles of menthol in 156 g - 1 mol
In 1 g of menthol number of moles - 1/156
Therefore in 5.0 g of menthol - 1/156 x 5 = 0.032 mol
therefore in 5.0 g of menthol there are 0.032 mol of menthol

b)
Molar mass of menthol - 156 g/mol
1 mol of menthol weighs 156 g
Therefore 1.56 mol of menthol weighs - 156 g/mol x 1.56 mol = 243.36 g

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2 years ago

The density of aluminum is 2.7 g.ml. what is the volume of 16.2 grams? HELP

lbvjy [14]

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density}$

From the question

density = 2.7 g/mL

mass of aluminum = 16.2 g

The volume is

$volume = \frac{16.2}{2.7}$

We have the final answer as

Hope this helps you

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3 years ago

If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m

lara [203]

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π $(100)^{2} / 4$ ;

We can take π as 3.14 and we get;

A = 3.14 X $(100)^{2} / 4$

Soving we get;

A = 7850 μ $m^{2}$

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ $m^{2}$ but;

here 1 μ $m^{2}$ = 7850 μ $m^{2}$ dye molecules.

Therefore, 10 fluorescent molecules will need;

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.

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3 years ago