Answer:
we know, at STP ( standard temperature and pressure).
we know, volume of 1 mole of gas = 22.4L
weight of 1 Litre of hydrogen gas = 0.09g
so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.
similarly,
weight of 2L of a gas = 2.88gm
so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g
hence, molecular weight of the gas = 32.256g
vapor density = molecular weight/2
= 32.256/2 = 16.128g
hence, vapor density of the gas is 16.128g.
Explanation:
The change in temperature of the metal is 6.1°C. Details about change in temperature can be found below.
<h3>How to calculate change in temperature?</h3>
The change in temperature of a substance can be calculated by subtracting the initial temperature of the substance from the final temperature.
According to this question, a 25.0 g sample of metal at 16.0 °C is warmed to 22.1 °C by 259J of energy.
This means that the change in temperature of the metal can be calculated as:
∆T = 22.1°C - 16°C
∆T = 6.1°C
Therefore, the change in temperature of the metal is 6.1°C.
Learn more about change in temperature at: brainly.com/question/19051558
#SPJ1
Mass of water = 80 x 18
= 1440 grams
Specific heat of water = 4.186 J/gK
Heat absorbed from water = mCpΔT
= 1440 x 4.186 x (21.6 - 18.1)
= 21.1 kJ
Moles of NH₄NO₃ = 3.53 / (14 + 4 + 14 + 16 x 3)
= 0.044 mol
Heat of solution = 21.1/0.044 kJ/mol
= 480 kJ/mol
Hello there!
I feel the correct answer is False.
Hope This Helps You!
Good Luck :)
