Complete Question
A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,000 km above the surface of the earth, and we assume it has an isotropic power output of 1 kW (although, in practice, satellite antennas transmit signals that are less powerful but more directional).
Reception devices pick up the variation in the electric field vector of the electromagnetic wave sent out by the satellite. Given the satellite specifications listed in the problem introduction, what is the amplitude E0 of the electric field vector of the satellite broadcast as measured at the surface of the earth? Use ϵ0=8.85×10^−12C/(V⋅m) for the permittivity of space and c=3.00×10^8m/s for the speed of light.
Answer:
The electric field vector of the satellite broadcast as measured at the surface of the earth is
Explanation:
From the question we are told that
The height of the satellite is
The power output of the satellite is
Generally the intensity of the electromagnetic radiation of the satellite at the surface of the earth is mathematically represented as
substituting values
This intensity of the electromagnetic radiation of the satellite at the surface of the earth can also be mathematically represented as
Where is the amplitude of the electric field vector of the satellite broadcast so
substituting values
They attract and stick together
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Answer:
No, The Moon, on the other hand, rotates once around its every 28 days, and once around the Earth in that same 28 days. The result of this combination is that the same side of the Moon is always facing the Earth.
Gravity is universal. This force of gravitational attraction is directly dependent upon the masses of both objects and inversely proportional to the square of the distance that separates their centers. This means that as you move away from an object the gravitational force decreases.