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katovenus [111]
3 years ago
8

Which point or points of view could be present in a business letter?

Physics
1 answer:
Studentka2010 [4]3 years ago
6 0

Answer:

?

Explanation:

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Define the reflection with diagram​
LekaFEV [45]

Answer:

The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray. If a perpendicular were to be drawn on reflecting surface, it would be called normal. The figure below shows the reflection of an incident beam on a plane mirror.

Explanation:

6 0
3 years ago
URGENT PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST !!!
kykrilka [37]

Answer:

C would be the answer

Explanation:

Hope this helps! :)

5 0
3 years ago
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A golf ball is rolling in the grass. What must happen to stop the ball from continuing to roll?
slamgirl [31]
The net force must be zero

This is in accordance to Newton's first law, which states that any object in motion will remain in motion and any object at rest will remain at rest unless acted upon by an unbalanced force. An unbalanced force is one where the net force is not zero. If no unbalanced force is applied to a moving object, it will keep moving forever. The reason that we do not observe this in our daily lives is due to friction acting as the unbalanced force.
4 0
3 years ago
A car accelerates from rest at 3.6 m/s 2 . How much time does it need to attain a speed of 5 m/s?
Olenka [21]

car starts from rest

v_i = 0

final speed attained by the car is

v_f = 5 m/s

acceleration of the car will be

a = 3.6 m/s^2

now the time to reach this final speed will be

t = \frac{v_f - v_i}{a}

t = \frac{5 - 0}{3.6}

t = 1.39 s

so it required 1.39 s to reach this final speed

6 0
4 years ago
An 1100kg car reached 30m/s in 9s from rest. What force did the engine provide?
malfutka [58]

Answer:

≅3666.67 N

Explanation:

Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,

a = acceleration acquired by the object.

a= (v-u)/t where v = final velocity, u = initial velocity and t = time taken

calculate a = (30-0)/9 ≅ 3.33 m/s2

Then F = 1100×a = 3666.67 N

3 0
3 years ago
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