Answer:
a= -1.2 m/s^2
Vi= 6.5 m/s
Vf= 0 m/s
t= 0-6.5/-1.2= <u>5.45 Sec</u>
Explanation:
Well its C, cant show you the work its in my head sorry.
Answer:
A. 70 m OS the correct one
A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)
This is the expression for escape velocity.
<span>It tells how hot it really feels when the relative humidity is factored in with the actual air temperature.
hope this helps</span>
