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lozanna [386]
4 years ago
5

From t=10.0 seconds to t=15.0 seconds, a space shuttle increased speed from 57 m/s to 99 m/s. What was the average acceleration

of the shuttle
Physics
1 answer:
Greeley [361]4 years ago
4 0

Answer:

   a = 8.4 m / s²

Explanation:

The mean acceleration is defined by

          a = (v_f- v₀) / (t_f - t₀)

where v are the final and initial velocities, respectively and t is the time interval

Let's apply this equation to our case

the final velocity is 99 m / s and the initial velocity is 57 m / s

         a = (99 - 57) / (15 - 10)

         a = 8.4 m / s²

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It was much later that evidences from plant and animal features that had similarity from two different planets came up that scientists began accepting the idea of continental drift.
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7 0
4 years ago
Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist
andreyandreev [35.5K]

Answer:

a) It is moving at 43.15\frac{m}{s^{2}} when reaches the ground.

b) It is moving at 101.44\frac{m}{s^{2}} when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

W=K_f-K_i (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

K=\frac{mv^2}{2} (2)

with m the mass and v the velocity.

Using (2) on (1):

W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

W=Fd=wd=mgd (4)

Using (4) on (3):

mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}

v_f=43.15\frac{m}{s^{2}}

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

-mgd=-\frac{mv_i^2}{2}

Solving for initial velocity (when the boulder left the volcano):

v_i=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*525}

v_i=101.44 \frac{m}{s^{2}}

3 0
3 years ago
When working with two-dimensional motion, choose the direction of _________________ to be a positive direction.
emmainna [20.7K]

Answer:

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6 0
2 years ago
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A bike is traveling to the left with the speed of 27 m/s when the rider slams on the brakes. The bike skids for 41.5 m with the
Darina [25.2K]

The acceleration of the bike is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Why?

Since after the rider slams the brakes, the bike came to a stop, we know that the acceleration is opposite to the velocity/movement.

We can use the following equation to calculate the acceleration:

v_{f}^{2}=v_{o}^{2}+2*a*d

So, substituting, we have: (let's consider negative to the left and positive to the right)

0=(-27\frac{m}{s} )^{2}+2*a*41.5m\\\\0=729\frac{m^{2} }{s^{2} }+83*a\\\\a=\frac{-729\frac{m^{2}}{s^{2}}}{83m}=-8.78\frac{m}{s^{2}}

The negative sign means that the acceleration's direction is opposite to the movement.

Hence, we have that the acceleration is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Have a nice day!

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Electrons move from the atoms in the cloth to the atoms in the balloon, causing the balloon to have a negative charge

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