We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 273 x 340 / 713
<span>P2 = 130 kPa</span>
Answer:
The maximum mass the bar can support without yielding = 32408.26 kg
Explanation:
Yield stress of the material (
) = 200 M Pa
Diameter of the bar = 4.5 cm = 45 mm
We know that yield stress of the bar is given by the formula
Yield Stress = ![\frac{Maximum load}{Area of the bar}](https://tex.z-dn.net/?f=%5Cfrac%7BMaximum%20load%7D%7BArea%20of%20the%20bar%7D)
⇒
=
---------------- (1)
⇒ Area of the bar (A) =
×![D^{2}](https://tex.z-dn.net/?f=D%5E%7B2%7D)
⇒ A =
× ![45^{2}](https://tex.z-dn.net/?f=45%5E%7B2%7D)
⇒ A = 1589.625 ![mm^{2}](https://tex.z-dn.net/?f=mm%5E%7B2%7D)
Put all the values in equation (1) we get
⇒
= 200 × 1589.625
⇒
= 317925 N
In this bar the
is equal to the weight of the bar.
⇒
=
× g
Where
is the maximum mass the bar can support.
⇒
= ![\frac{P_{max} }{g}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7Bmax%7D%20%7D%7Bg%7D)
Put all the values in the above formula we get
⇒
= ![\frac{317925}{9.81}](https://tex.z-dn.net/?f=%5Cfrac%7B317925%7D%7B9.81%7D)
⇒
= 32408.26 Kg
There fore the maximum mass the bar can support without yielding = 32408.26 kg
Answer:
The answer is the 3rd option!
Answer:
The male gamete is smaller in comparison to that of the female gamete.
The male gamete is conical from the front while the female gamete is spherical.
The cytoplasm in the male gamete is less in comparison to that of the female gamete.
The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.
The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.
The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.
Explanation:
Answer:
The resistors will be in parallel to produce a net resistance of 4ohm and current in 20 ohm resistor will be 0.5A and 5ohm resistor will be 2A.
Explanation:
We are given 10 voltage power source and we have two Resistors with resistance of 20 ohm and 5ohm.
We need to find the orientation in which these two resistors would be arranged so that the circuit could get a current of 2.5Ampere.
Using ohm's law we have
V = I*R
V= voltage
I= current
R= resistance
10 = 2.5*R
R = 10/2.5 = 4ohm
that means we need a total of 4ohm resistance from these two resistors.
since the net Resistance(4ohm) is lower than the smallest resistance(5ohm) available that means the orientation of the resistors will be in parallel.
![\frac{1}{R} = \frac{1}{R1} +\frac{1}{R2}\\ = \frac{1}{20} +\frac{1}{5}\\ \\ = \frac{1+4}{20} =\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR%7D%20%3D%20%5Cfrac%7B1%7D%7BR1%7D%20%2B%5Cfrac%7B1%7D%7BR2%7D%5C%5C%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Cfrac%7B1%7D%7B20%7D%20%2B%5Cfrac%7B1%7D%7B5%7D%5C%5C%20%5C%5C%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Cfrac%7B1%2B4%7D%7B20%7D%20%3D%5Cfrac%7B1%7D%7B4%7D)
R(net) =4ohm
Now the orientation of the resistors are in parallel so the current will be divided.
we know that the current will divide in opposite manner the arm which provides more resistance less current will flow from there and vice versa.
We know that the voltage in parallel remains same
In 20 ohm resistance
again using ohms law
V = i1*R1
10 = i1*20
i1 = 0.5A
in 5ohm resistor
V=i2*R2
10 = I2*5
i2 =2A
and i1+i2 = 0.5+2= 2.5A which means our calculation is correct.
Therefore the resistors will be in parallel to produce a net resistance of 4ohm and current in 20 ohm resistor will be 0.5A and 5ohm resistor will be 2A.