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ki77a [65]
3 years ago
8

PLSSS HELP

Chemistry
2 answers:
lions [1.4K]3 years ago
5 0
Sun, use fusion to combine hydrogen atoms into helium atoms,
Trava [24]3 years ago
3 0

Answer:

1. A) Atoms gain valence electrons to form anions.

2. D) 50.94151 amu

3. D) elements in clouds of gas and dust in deep space.

4. D) silicon

Explanation:

Hello,

1. In this question, we consider that anions are chemical ions negatively charged, it means that they gain valence electrons to increase their oxidation states, thus the answer is: A) Atoms gain valence electrons to form anions.

2. In order to compute the required average atomic mass, we must consider the mass of each isotope and its percentage as shown below:

M=50amu*0.0025+50.944amu*0.9975\\M=50.94151amu

Therefore answer is D).

3. In this case, the answer is: D) elements in clouds of gas and dust in deep space, as each element has its own atomic emission spectrum, therefore one can identify the spectra in order to determine which elements are present.

4. Since helium is obtained via the atomic fusion of two hydrogen atoms, nickel can be obtained via the atomic fusion of two silicon atoms since each silicon has 14 protons and electrons, thus, if we fusion them we obtain 28 protons and electrons, validating the existence of a nickel atom.

Best regards.

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How do anion formation and valence electrons relate?
vagabundo [1.1K]

Answer:

A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.

7 0
2 years ago
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Which color of light is diffracted at a greater angle from a diffraction grating, red or yellow?
Anit [1.1K]
The color of light that will be diffracted at a greater angle from a diffracting grating is THE YELLOW COLOR.
This is because, the degree of diffraction depend on the wavelength of light and light color with shorter wavelength are diffracted at a larger angle than those with longer wavelengths. The wavelength of the yellow color is much more smaller than that of the red color.
3 0
3 years ago
Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
BARSIC [14]

Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0
3 years ago
The protection of animals, plants, and natural resources
In-s [12.5K]

Answer:

The protection of animals, plants, and natural resources

D. conservation

(for science)

Explanation:

Brainlist plz

5 0
2 years ago
Read 2 more answers
Guys, please, please help!!
shutvik [7]
Ookay 

1) T 
2) T
3) F

Hope i helped :)

6 0
3 years ago
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