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aleksandr82 [10.1K]
3 years ago
15

What is the smallest particle representing water?

Chemistry
2 answers:
sveticcg [70]3 years ago
5 0
Your answer is: A molecule. 
horrorfan [7]3 years ago
4 0
Water is a compound that is made up of oxygen and hydrogen atoms, therefore the smallest particle of water is water molecule. The smallest particle representing water is written as H2O. H2O is the smallest unit to which water can be split while still retaining the properties of water.
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I’ll give the brainliest
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Answer:

Water gradually degrades them until the metal parts rust and the other materials deteriorate.

Explanation:

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3 years ago
Particles of matter how have both potential and kinetic energy is that true or false?
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False: No,any particles of matter do not have any potential or kinetic energy.

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Where would the electrons in the 3d sublevel be found? Possibly in any shell only in the n = 3 energy level in energy levels &gt
postnew [5]

Answer:

In the n = 3 energy level

Explanation:

There's is no further explanation for this.

All the electrons in an energy level are distribuited according to the period in the periodic table they are.

So, if we have an atom in period 1, like Hydrogen (H), that atom would only have 1 level energy (n = 1) and in that level, we only have the sub level 1s.

Electrons in the 3d sublevel, are found mostly in all the transition metals of period 3, and it can go from 1 to 10 electrons. To be with the 3d sub level it's neccesary that the energy level to be 3.

energy levels beyond that, like n = 4, we have electrons occupying the 3d sub level, so, primordly, the 3d is found only in energy level 3.

Hope this helps

4 0
3 years ago
Where does nearly all life get its energy from? *<br> Oxygen<br> A.Sun<br> B.Produce<br> C.Soil
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Read 2 more answers
The normal boiling point of iodomethane, CH3I, is 42.43 8C, and its vapor pressure at 0.00 8C is 140. Torr. Calculate (a) the st
tigry1 [53]

Answer:

a=28600J; b=90.6 J/K; c=402 torr

Explanation:

(a) considering the data given

 Vapour pressure P1 =0  at Temperature T1 = 42.43˚C,

Vapour pressure P2 = 273.15 at Temperature T2= 315.58 K)

Using the Clausius-Clapeyron Equation

ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

In 760/140 = ΔH/8.314 J/mol/K  × (1/315.58K -- 1/273.15K)

ΔH vap= +28.6 kJ/mol or 28600J

(b) using the Equation ΔG°=ΔH° - TΔS to solve forΔS.

Since ΔG at boiling point is zero,

ΔS =(ΔH°vap/Τb)

 ΔS = 28600 J/315.58 K

= 90.6 J/K

(c) using ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

ln P298 K/1 atm =  28600 J/8.314 J/mol/K × (1/298.15K - 1/315.58K)

P298 K = 0.529 atm

                = 402 torr

8 0
3 years ago
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