To answer this problem first is to analyze and understand the problem first and then consider the given and also the gravity that is exert in the ball. Base on my calculation and the use of the formulas the answer are the following: A. The initial velocity is <span>29.43 m/s b. The height it reaches is 132.435m</span>
The capacitance of any capacitor, by definition, is as follows:
Applying Gauss'Law and the definition of electric potential, it can be showed that the capacitance of a parallel-plate capacitor can be expressed as follows:
Where εr is the dielectric constant of the material that fills the space between the plates, A is the area of one of the plates, and d, is the separation between them.
Replacing by the givens in (2) we can find the value of the capacitance C, as follows:
Replacing the values of C and V in (1), we can solve for Q, as follows:
As the outer surface is at a higher potential that the inside surface, the charge on it must be positive, and is equal to +1.4 pC.