Answer:
Zero work done,since the body isn't acting against or by gravity.
Explanation:
Gravitational force is usually considered as work done against gravity (-ve) and work by gravity ( +ve ) and also When work isn't done by or against gravity work done in this case is zero.
Gravitational force can be define as that force that attracts a body to any other phyical body or system that have mass.
The planet been considered as our system in this case is assumed to have mass, and ought to demonstrate such properties associated with gravitational force in such system. Such properties include the return of every object been thrown up as a result of gravity acting downwards. The orbiting nature of object along an elliptical part when gravitational force isn't acting on the body and it is assumed to be zero.
Answer:
Stationary Front, warm front, cold front, Occluded Front.
Explanation:
Stationary Front. When the surface position of a front does not change (when two air masses are unable to push against each other; a draw), a stationary front is formed.
cold front is the leading edge of a cooler mass of air at ground level that replaces a warmer mass of air and lies within a pronounced surface trough of low pressure. It often forms behind an extratropical cyclone (to the west in the Northern Hemisphere, to the east in the Southern), at the leading edge of its cold air advection pattern—known as the cyclone's dry "conveyor belt" flow. Temperature differences across the boundary can exceed 30 °C (86 °F) from one side to the other. When enough moisture is present, rain can occur along the boundary. If there is significant instability along the boundary, a narrow line of thunderstorms can form along the frontal zone. If instability is weak, a broad shield of rain can move in behind the front, and evaporative cooling of the rain can increase the temperature difference across the front. Cold fronts are stronger in the fall and spring transition seasons and weakest during the summer.
A warm front is a density discontinuity located at the leading edge of a homogeneous warm air mass, and is typically located on the equator-facing edge of an isotherm gradient. Warm fronts lie within broader troughs of low pressure than cold fronts, and move more slowly than the cold fronts which usually follow because cold air is denser and less easy to remove from the Earth's surface. This also forces temperature differences across warm fronts to be broader in scale. Clouds ahead of the warm front are mostly stratiform, and rainfall gradually increases as the front approaches. Fog can also occur preceding a warm frontal passage. Clearing and warming is usually rapid after frontal passage. If the warm air mass is unstable, thunderstorms may be embedded among the stratiform clouds ahead of the front, and after frontal passage thundershowers may continue. On weather maps, the surface location of a warm front is marked with a red line of semicircles pointing in the direction of travel.
In meteorology, an occluded front is a weather front formed during the process of cyclogenesis. The classical view of an occluded front is that they are formed when a cold front overtakes a warm front, such that the warm air is separated (occluded) from the cyclone center at the surface. The point where the warm front becomes the occluded front is called the triple point; a new area of low-pressure that develops at this point is called a triple-point low. A more modern view of the formation process suggests that occluded fronts form directly during the wrap-up of the baroclinic zone during cyclogenesis, and then lengthen due to flow deformation and rotation around the cyclone.
Answer:
120 J
Explanation:
KE = mv²/2 = (0.15 kg * [40 m/s]²)/2 = 120 J
To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.
So things our data are given by
![N_1 = 160](https://tex.z-dn.net/?f=N_1%20%3D%20160)
![N_2 = 1400](https://tex.z-dn.net/?f=N_2%20%3D%201400)
![\Delta V_{1rms} = 62V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B1rms%7D%20%3D%2062V)
PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by
![\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}](https://tex.z-dn.net/?f=%5Cfrac%7BN_1%7D%7BN_2%7D%20%3D%20%5Cfrac%7B%5CDelta%20V_%7B1rms%7D%7D%7B%5CDelta%20V_%7B2rms%7D%7D)
So the voltage for transformer 2 would be given by,
![\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7BN_2%7D%7BN_1%7D%20%5CDelta%20V_%7B1rms%7D)
PART B) To express the number value we proceed to replace with the previously given values, that is to say
![\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7BN_1%7D%7BN_2%7D%20%5CDelta%20V_%7B1rms%7D)
![\Delta V_{2rms} = \frac{1400}{160} 62V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7B1400%7D%7B160%7D%2062V)
![\Delta V_{2rms} = 1446.66V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%201446.66V)
Answer:
Perfectly inelastic collision
Explanation:
There are two types of collision.
1. Elastic collision : When the momentum of the system and the kinetic energy of the system is conserved, the collision is said to be elastic. For example, the collision of two atoms or molecules are considered to be elastic collision.
2. Inelastic collision: When the momentum the system is conserved but the kinetic energy is not conserved, the collision is said to be inelastic. For example, collision of a ball with the mud.
For a perfectly elastic collision, the two bodies stick together after collision.
Here, the meteorite collide with the Mars and buried inside it, the collision is said to be perfectly inelastic. here the kinetic energy of a body lost completely during the collision.