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attashe74 [19]
3 years ago
13

You have been posted to a remote region of space to monitor traffic. Near the end of a quiet shift, a spacecraft streaks past. Y

our laser-based measuring device reports the spacecraft’s length to be 85 m. The identification transponder reports it to be the NCXXB12, a cargo craft of proper length 100 m. In transmitting your report to headquarters, what speed should you give for this spacecraft?
Physics
1 answer:
natima [27]3 years ago
3 0

Answer:

The value is v =1.58 *10^{8} \  m/s

Explanation:

From the question we are told that

The length of the spacecraft streaks is L_i =  85 \  m

The proper length of the spacecraft streaks L_p  =  100 \  m

Generally from the equation of relativity of length contraction

L_i  =  L_p  *  \sqrt{1 - \frac{v^2}{c^2} }

Here c is the speed of light with value c =  3.0 *10^{8} \  m/s^2

v is the velocity of the spacecraft

So

\frac{v^2}{c^2}  =  1 - \frac{L_i^2}{L_p^2 }

=> \frac{v^2}{c^2}  =  \frac{L_p^2 - L_i^2}{L_p^2}

=> \frac{v^2}{c^2}  =  \frac{100^2 - 85^2}{100^2}

=> \frac{v^2}{c^2} =  0.2775

=>  v =  \sqrt{0.2775c^2}

=>  v = 0.5268c

=>  v = 0.5268 *  3.0*10^{8}

=>  v =1.58 *10^{8} \  m/s

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Answer: 31 m/s due east

Explanation: this question can be solved using the law of conservation of linear momentum.

This law states that in a closed or isolated system, during collision, the vector sum of momentum before collision equals the vector sum of momentum after collision.

Momentum = mass × velocity

From our question, our parameters before collision are given below as

Mass of car = mc = 1400kg

Speed of car =vc = 31 m/s (due east)

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Velocity of truck = vt = 25 m/s ( due east )

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Velocity of truck = 34 m/s ( due east )

Vector sum of momentum before collision is given as

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After collision the truck is seen to move faster (v = 34 m/s) which implies that the car also moves due east .

1400 (v) + 2400(25) .... A positive value is between both momenta because they are in the same direction.

After collision, we have that

1400v + 60000

Vector sum of momentum before collision = vector sum of momentum after collision

103400 = 1400v + 60000

103400 - 60000 = 1400v

43400 = 1400v

v = 43400/ 1400

v = 31 m/s due east

4 0
3 years ago
According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

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now we also know that

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Answer:

The minimum wall thickness required for the spherical tank is 0.0189 m

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d = inside diameter = 8.1 m

P = internal pressure = 1.26 MPa

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