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attashe74 [19]
3 years ago
13

You have been posted to a remote region of space to monitor traffic. Near the end of a quiet shift, a spacecraft streaks past. Y

our laser-based measuring device reports the spacecraft’s length to be 85 m. The identification transponder reports it to be the NCXXB12, a cargo craft of proper length 100 m. In transmitting your report to headquarters, what speed should you give for this spacecraft?
Physics
1 answer:
natima [27]3 years ago
3 0

Answer:

The value is v =1.58 *10^{8} \  m/s

Explanation:

From the question we are told that

The length of the spacecraft streaks is L_i =  85 \  m

The proper length of the spacecraft streaks L_p  =  100 \  m

Generally from the equation of relativity of length contraction

L_i  =  L_p  *  \sqrt{1 - \frac{v^2}{c^2} }

Here c is the speed of light with value c =  3.0 *10^{8} \  m/s^2

v is the velocity of the spacecraft

So

\frac{v^2}{c^2}  =  1 - \frac{L_i^2}{L_p^2 }

=> \frac{v^2}{c^2}  =  \frac{L_p^2 - L_i^2}{L_p^2}

=> \frac{v^2}{c^2}  =  \frac{100^2 - 85^2}{100^2}

=> \frac{v^2}{c^2} =  0.2775

=>  v =  \sqrt{0.2775c^2}

=>  v = 0.5268c

=>  v = 0.5268 *  3.0*10^{8}

=>  v =1.58 *10^{8} \  m/s

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aev [14]

Answer:

Explanation:

Given

charge of first body q_1=2.5\ mu C

charge of second body q_2=-3.5\ mu C

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third Particle which charge +q must be placed left of 2.5\mu C because it will repel the q charge while -3.5\mu C will attract it

suppose it is placed at a distance of x m

F_{1q}=\frac{kq(2.5)}{x^2}

F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}

F_{1q}+F_{2q}=0

\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0

\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}

\frac{0.6+x}{x}=(\frac{3.5}{2.5})^{0.5}

0.6+x=1.1832x

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5 0
3 years ago
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Hope this helps

7 0
4 years ago
What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol
san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

Q=\frac{\Delta H}{n}

where,

Q = energy absorbed = 27.2 kJ

\Delta H = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

27.2kJ=\frac{6.01kJ/mol}{n}

n=0.221mol

Now we have to calculate the mass of ice.

\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}

Molar mass of ice = 18.02 g/mol

\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g

Thus, the mass of ice melted can be, 3.98 grams.

3 0
4 years ago
An object weighing 49 N is pushed across a floor by a force of 12 N. What is the acceleration of the object?
NISA [10]

Answer:

Explanation:

Given parameters:

Weight of object  = 49N

Force applied = 12N

Unknown:

Acceleration of object  = ?

Solution:

The acceleration of the object is found by dividing the force by the weight;

 Acceleration  = \frac{12}{49}   = 0.25m/s²

3 0
3 years ago
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