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ki77a [65]
3 years ago
7

How will the charge on the balloons affect their behavior? explain your reasoning

Physics
2 answers:
nika2105 [10]3 years ago
6 0

Answer:

They would repel each other.

Explanation:

In both the Balloons given in the  picture there are excess of negative charge or we can say that both the balloons are likely charged. Then according to the law of electrostatics like charged objects will repel each other. Hence, the balloons in the figure will be repelled by each other, that is they will move away from each other.

Debora [2.8K]3 years ago
4 0
The balloons will repel since the two balloons are mostly negatively charged so the the net force woukd be repulsive causing them to repel and move away from each other
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Se coloca una piedra de 600 g en una Honda de 50 cm y se la hace girar a una velocidad de 4 m/s. Dibuja la fuerza que ejerce la
Dima020 [189]

Answer:

Fc = 19.2 N

Explanation:

In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

F_c=m\frac{v^2}{r}

m: mass of the rock = 600g = 0.6 kg

v: tangential velocity of the Honda = 4m/s

r: radius of the Honda = 50cm = 0.5m

You replace the values of m, r and v in the equation for Fc:

F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N

hence, the force has a magnitude of 19.2 N

If the rock would have more mass the centripetal force would be higher

4 0
3 years ago
Why are scientific models important ?
Sindrei [870]
They help scientists explain concepts that are difficult to observe.
7 0
3 years ago
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if a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?
djyliett [7]

Answer:

0.1 N

Explanation:

Considering the relationship between force,

spring constant and extension as defined by Hook's law

The force F=xk as from Hooke's law where F is the force of the spring, k is spring constant and x is extension or compression. Substituting 2 N/m for k and 5cm which is equivalent to 0.05 m for extention x then the force will be

F=2*0.05=0.1 N

4 0
3 years ago
The brightness of a star is determined
nasty-shy [4]
100% C . By size and distance
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2 years ago
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An electric field of 280000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -
nordsb [41]
<h2>The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.</h2>

Explanation:

Electric field is the ratio of force and charge.

Electric field, E = 280000 N/C

Charge, q = -7.9 C

We have

                 E=\frac{F}{q}\\\\280000=\frac{F}{7.9}\\\\F=280000\times 7.9\\\\F=2.21\times 10^6N

The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.

4 0
3 years ago
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